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RoseWind [281]
3 years ago
5

70 POINTS HELP PHYSICS THE PICTURE HAS THE QUESTION AND POSSIBLE CHOICES

Physics
1 answer:
snow_tiger [21]3 years ago
6 0

Answer:

0.3 m/s

Explanation:

0.5 - 0.2 = .3

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Which of the following is the correct description of momentum?
victus00 [196]

Answer:

The product of mass and velocity is the correct answer

Explanation:

Momentum is defined as mass × velocity

p = mv

7 0
3 years ago
20 miles per hour north is an example of ______
timofeeve [1]
B. It's an example of velocity due to the fact that it has a measurement of speed, divided by time, and has a specific direction. Acceleration doesn't have any direction on it, but has speed divided by time. C and D have a different mode of measurement despite of the fact that it still needs meters/miles/km.
4 0
3 years ago
Explain the application of pascals law<br>​
Marta_Voda [28]

Answer:

pplications of Pascal’s Law  

Hydraulic Lift: The image you saw at the beginning of this article is a simple line diagram of a hydraulic lift. This is...

The construction is such that a narrow cylinder (in this case A) is connected to a wider cylinder (in this case B). They...

Pressure applied at piston A is transmitted equally to piston B without diminishing, on use of an incompressible fluid.

Explanation:

6 0
3 years ago
A circus tightrope walker weighing 800 N is standing in the middle of a 15 meter long cable stretched between two posts. The cab
Lorico [155]

Answer:

T = 10010 N

Explanation:

To solve this problem we must use the translational equilibrium relation, let's set a reference frame

X axis

       Fₓ-Fₓ = 0

       Fₓ = Fₓ

whereby the horizontal components of the tension in the cable cancel

Y Axis  

        F_{y} + F_{y} - W =0

        2F_{y} = W

let's use trigonometry to find the angles

        tan θ = y / x

        θ = tan⁻¹ (0.30 / 0.50 L)

        θ = tan⁻¹ (0.30 / 0.50 15)

        θ = 2.29º

the components of stress are

         F_{y} = T sin θ

we substitute

       2 T sin θ = W

       T = W / 2sin θ

        T = \frac{ 800}{ 2sin 2.29}

        T = 10010 N

4 0
3 years ago
The magnitude of the magnetic flux through the surface of a circular plate is 6.80 10-5 T · m2 when it is placed in a region of
PIT_PIT [208]

Answer:

B = 4.1*10^-3 T = 4.1mT

Explanation:

In order to calculate the strength of the magnetic field, you use the following formula for the magnetic flux trough a surface:

\Phi_B=S\cdot B=SBcos\alpha        (1)

ФB: magnetic flux trough the circular surface = 6.80*10^-5 T.m^2

S: surface area of the circular plate = π.r^2

r: radius of the circular plate = 8.50cm = 0.085m

B: magnitude of the magnetic field = ?

α: angle between the direction of the magnetic field and the normal to the surface area of the circular plate = 43.0°

You solve the equation (1) for B, and replace the values of the other parameters:

B=\frac{\Phi_B}{Scos\alpha}=\frac{6.80*10^{-5}T.m^2}{(\pi (0.085m)^2)cos(43.0\°)}\\\\B=4.1*10^{-3}T=4.1mT

The strength of the magntetic field is 4.1mT

4 0
3 years ago
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