Ask question

Ask question

All categories

4 years ago

10

There are many environmental benefits to using nuclear power. One is not an environmental benefit of nuclear power. That is:

1 answer:

FinnZ [79.3K]4 years ago

6 0

The Answer is here
Nuclear energy has no place in a safe, clean, sustainable future. Nuclear energy is both expensive and dangerous, and just because nuclear pollution is invisible doesn't mean it's clean

You might be interested in

mamaluj [8]

Answer:

What is an electromagnetic wave

Explanation:

Electromagnetic radiation is also more commonly known as light, light travels in waves- and light travels at the same speed as electromagnetic waves. :)

8 0

3 years ago

Read 2 more answers

Which single force acts on a object in a free fall

11Alexandr11 [23.1K]

Answer:

weight!!!! Free fall is the motion of a body where its weight is the only force acting on an object.

4 0

3 years ago

A sample of polonium-210 was left for 414 days.

jenyasd209 [6]

Answer:

PO(1) = PO(0) / 2 1 refers to 1 half life of PO(0)

PO(2) = PO(1) / 2 = P(0) / 4 amount of PO left after 2 half-lives

PO(3) = PO(2) / 2 = PO(0) / 8 amount of PO left after 3 half-lives

414 da / 138 da = 3 3 half-lives pass in 414 da

PO(0) = 8 PO(3) = 8 * 1.45E-4 g = 1.16E-3 g = .00116 g after 414 days

6 0

3 years ago

To practice problem-solving strategy 22.1: gauss's law. an infinite cylindrical rod has a uniform volume charge density ρ (where

BabaBlast [244]

Let say the point is inside the cylinder

then as per Gauss' law we have

$\int E.dA = \frac{q}{\epcilon_0}$

here q = charge inside the gaussian surface.

Now if our point is inside the cylinder then we can say that gaussian surface has charge less than total charge.

we will calculate the charge first which is given as

$q = \int \rho dV$

$q = \rho * \pi r^2 *L$

now using the equation of Gauss law we will have

$\int E.dA = \frac{\rho * \pi r^2* L}{\epcilon_0}$

$E. 2\pi r L = \frac{\rho * \pi r^2* L}{\epcilon_0}$

now we will have

$E = \frac{\rho r}{2 \epcilon_0}$

Now if we have a situation that the point lies outside the cylinder

we will calculate the charge first which is given as it is now the total charge of the cylinder

$q = \int \rho dV$

$q = \rho * \pi r_0^2 *L$

now using the equation of Gauss law we will have

$\int E.dA = \frac{\rho * \pi r_0^2* L}{\epcilon_0}$

$E. 2\pi r L = \frac{\rho * \pi r_0^2* L}{\epcilon_0}$

now we will have

$E = \frac{\rho r_0^2}{2 \epcilon_0 r}$

7 0

4 years ago

Frequency x wavelength = ?

Oduvanchick [21]

the answer would be velocity

7 0

4 years ago

Read 2 more answers