92
given 2a² + 5b²
substitute given values for a and b into the expression
2(- 6)² + 5(2)² = (2 × 36 ) + (5 × 4) = 72 + 20 = 92
Volume of a quadrangular pyramid=(1/3)bh
b=base
h=height
b=area of the base=area of a square=8.4 ft * 8.4 ft=70.56 ft²
Pythagoras theorem:
hypotenuse²=leg₁² + leg₂²
data:
hypotenuse=9.6 ft
leg₁=height=h
leg₂=8.4 ft /2=4.2 ft
(9.6 ft)²= h² + (4.2 ft)²
92.16 ft²=h²+17.64 ft²
h²=92.16 ft²-17.64 ft²
h²=74.52 ft²
h=√(74.52 ft²)=8.63 ft.
Volume of this quadrangular pyramid=(1/3)(70.56 ft²)(8.63 ft)=202.9 ft³≈202.3 ft³
Answer: ≈202.3 ft³
The range refers to the value of y for which x is define.
So let y=f(x),

Try making x the subject to obtain,

x is defined for all real values of y greater than
0.
Hence the correct answer is D.
Answer:
21.0%
Step-by-step explanation:
Answer:
The closest to the volume of cylinder is <u>63 in.³</u>.
Step-by-step explanation:
Given:
Cylinder with a height of 11 inches and a circumference of 8 1/2 inches.
Now, to find the volume.
As circumference is given we get the radius by putting formula:
Circumference = 8 1/2 inches = 17/2 inches.
Let the radius be 
<em>Taking the value of π = 3.14.</em>


<em>Dividing both sides by 6.28 we get:</em>

So, radius = 1.35 inches.
Height = 11 inches.
Now, putting the formula to get the volume:





<u><em>Hence, the volume of cylinder = 63 inches³ (approximately).</em></u>
Therefore, the closest to the volume of cylinder is 63 in.³.