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Firdavs [7]
3 years ago
15

Three times a number is 4 more than twice the number

Mathematics
1 answer:
Gelneren [198K]3 years ago
5 0

Answer:

3n = 2n + 4

Step-by-step explanation:

That is that as an equation.

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Is negitive 1.8 greater than negitive 2.1
Llana [10]
Unlike positives, with negatives, the larger a number is, the smaller it is.

Example : 
4 > 2

-4 < -2

so -1.8 is GREATER then -2.1

here is a tip :
picture ur number line....plot -2.1....any number to the right is greater and any number to the left is less...and since -1.8 is to the right of -2.1, it is greater then -2.1
3 0
3 years ago
Read 2 more answers
A tablet weighs 1.23 pounds. What is its weight written as a mixed number?
garik1379 [7]
If a tablet weighs 1.23 pounds, the weight written as a mixed number would be, 1 as the whole number and 23 is in the hundreds place, so you would write, 1 and 23/100.
3 0
3 years ago
Range, mode, MAD, median IQR, mean
Jlenok [28]

Answer:

range=8, mode=1  Median=3 mean=4

Step-by-step explanation:

range= subtract largest from smallest

mode= most frequent

median= middle in an ordered data set

Mean= add them all up and divide by how many you addded up

6 0
2 years ago
Read 2 more answers
HELP ME ASAP!!!!!!!!
Marina CMI [18]

Answer:

Step-by-step explanation:

1) 30 : 100 = x : 299

x = (30 x 299)/100

x = 89,70 $

2) 299 - 89,70 = 209,30 $

3)  5 : 100 = x : 209,30

x = 10,465 $

209,30 + 10,465 = 219,77 $

5 0
3 years ago
Assume that​ women's heights are normally distributed with a mean given by mu equals 62.5 in​,and a standard deviation given by
Misha Larkins [42]

Answer:

(a) 0.5899

(b) 0.9166

Step-by-step explanation:

Let X be the random variable that represents the height of a woman. Then, X is normally distributed with  

\mu = 62.5 in

\sigma = 2.2 in

the normal probability density function is given by  

f(x) = \frac{1}{\sqrt{2\pi}2.2}\exp{-\frac{(x-62.5)^{2}}{2(2.2)^{2}}}, then

(a) P(X < 63) = \int\limits_{-\infty}^{63}f(x) dx = 0.5899

   (in the R statistical programming language) pnorm(63, mean = 62.5, sd = 2.2)

(b) We are seeking P(\bar{X} < 63) where n = 37. \bar{X} is normally distributed with mean 62.5 in and standard deviation 2.2/\sqrt{37}. So, the probability density function is given by

g(x) = \frac{1}{\sqrt{2\pi}\frac{2.2}{\sqrt{37}}}\exp{-\frac{(x-62.5)^{2}}{2(2.2/\sqrt{37})^{2}}}, and

P(\bar{X} < 63) = \int\limits_{-\infty}^{63}g(x)dx = 0.9166

(in the R statistical programming language) pnorm(63, mean = 62.5, sd = 2.2/sqrt(37))

You can use a table from a book to find the probabilities or a programming language like the R statistical programming language.

4 0
3 years ago
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