Answer:
The result is that you eliminate the 7y term and thus can solve for x.
x = -28/3
y = 30/7
Step-by-step explanation:
-20 + 7y = 10
3x + 7y = 2
subtract... elimination method
-20 - 3x = 8
-3x = 28
x = -28/3
-20 + 7y = 10
7y = 30
y = 30/7
Answer:
PQT and TQS
Step-by-step explanation:
they must supplement each other to get the 90
Answer:
a=7
Step-by-step explanation:
Given,
6a-7=3a+14
or,6a-3a=14+7
or,3a=21
or,a=7 [ANSWER]
9) It helps to draw a picture. Since one angle is 60°, the other angle is 120°. When you draw the ddiagonal lines, you will see that you end up with a 30°-60°-90° triangle where √3 is the hypotenuse. The longest diagonal will be across from the 60° angle, which will be length a√3. The length of the hypotenuse is 2a. (Remember: a, a√3, 2a are lengths for this special triangle)
2a = √3 → a = √3/2.
side across from 60° = a√3 = (√3/2)·√3 → side from across 60° = 3/2
Remember that this is only one-half of the diagonal of the rhombus so multiply that by 2.
Length of longest diagonal is 3.
10) Volume of a square pyramid = (1/3) B · h, where B is the area of the base
200 = (1/3)B(12)
50 = B
Since the base is a square, then each side is √50 (which equals 5√2).
Now, to find the lateral edge, use Pythagorean Theorem (a² + b² = c²).
Height (a) = 12, base (b) = 5√2, and lateral edge (c) is unknown.
(12)² + (5√2)² = c²
144 + 50 = c²
194 = c²
√194 = c
Lateral edge is √194.
