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Papessa [141]
3 years ago
10

During a figure skating routine, Jackie and Peter skate apart with an angle of 15° between them. Jackie skates for 5 meters and

Peter skates for 7 meters. How far apart are the skaters? Round to the nearest hundredth of a meter.
Mathematics
1 answer:
Fantom [35]3 years ago
7 0

Answer:

Ans = 2.53m

Step-by-step explanation:

It is a simple law of Cosine, on a right-angle triangle draw the length as 5 and the base as 7 the angle is 15°. Find x.

So x = 5² +7² - 2 (5) (7)cos 15°

Solve this and you get your answer.

Hope this was helpful :)

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You would basically go back and trace all your steps, that's what I do. And if your answer seems reasonable then you have the right answer but if your work doesn't match the answer than you've messed up.   I hope I helped if I did like my answer and comment down below thx

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HELPPPP I DONT HAVE MUCH TIME the question is what is the rate of change of the function?
Arada [10]

Answer:

2

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
What is the y-coordinate of the solution for the system of equations? x−y=−11 y+7=−2x
ICE Princess25 [194]

Answer:

y= 5

Step-by-step explanation:

Given the system of equations:

x-y=-11

y+7=-2x

In order to find the y coordinate of the solution we must first find the solution to this system of equations. We first start by solving one of the given equations and then substitute the answer of that into the second equation and further solve to get the final answers.

x=y=-11

y+7=-2x

y+7=-2x

+ -7

y = -2x - 7

x - y = -11

y = -2x-7

x-(-2x-7)=-11

x--2x=x+2x=3x

3x+7=-11

-7

-11+-7=-18

3x=-18

\div3

-18\div3=-6

x=-6

y=-2x-7

y=(-2)(-6)-7

-2\times-6=12-7=5

y=5

Hope this helps.

7 0
2 years ago
What is the probability that the spinner will land on black?
zavuch27 [327]
2/5, five different areas and two are black
6 0
4 years ago
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The average value of a function f over the interval [−1,2] is −4, and the average value of f over the interval [2,7] is 8. What
Anna71 [15]

The average value of a continuous function f(x) over an interval [a, b] is

\displaystyle f_{\mathrm{ave}[a,b]} = \frac1{b-a}\int_a^b f(x)\,dx

We're given that

\displaystyle f_{\rm ave[-1,2]} = \frac13 \int_{-1}^2 f(x) \, dx = -4

\displaystyle f_{\rm ave[2,7]} = \frac15 \int_2^7 f(x) \, dx = 8

and we want to determine

\displaystyle f_{\rm ave[-1,7]} = \frac18 \int_{-1}^7 f(x) \, dx

By the additive property of definite integration, we have

\displaystyle \int_{-1}^7 f(x) \, dx = \int_{-1}^2 f(x)\,dx + \int_2^7 f(x)\,dx

so it follows that

\displaystyle f_{\rm ave[-1,7]} = \frac18 \left(\int_{-1}^2 f(x)\,dx + \int_2^7 f(x)\,dx\right)

\displaystyle f_{\rm ave[-1,7]} = \frac18 \left(3\times(-4) + 5\times8\right)

\displaystyle f_{\rm ave[-1,7]} = \boxed{\frac72}

7 0
2 years ago
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