<h2>~<u>Solution</u> :-</h2>
Here, it is given that the bag contains 25 paise coins and 50 paise coins in which, 25 paise coins are 6 times than that of 50 paise coins. Also, the total money in the bag is Rs. 6.
- Hence, we can see that, here, we have been given the linear equation be;
Let the number of coins of 50 paise will be $ x $ and the number of coins of 25 paise will be $ 6x $ as given. . .
Hence,




- Hence, the number of 50 paise coins will be <u>2</u>. And, 6 times of two be;

- Hence, the number of 25 paise coins will be <u>12</u>.
4 = (r-2) t
8 = (r+2) t
4 = (r-2) * [8/(r+2)]
4 = (8r-16)/ (r+2) . . .multiply by 2
4r + 8 = 8r - 16
4r = 24
r = 6
hope this helps
7/10s of 40 would be 28 so that leave 12 hours to work inside