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Nataliya [291]
4 years ago
13

How to find the length when the perimeter and width is given

Mathematics
1 answer:
Gelneren [198K]4 years ago
7 0

Answer:

Step-by-step explanation:

Step 1:Width x 2

Step 2:Perimeter — step 1

Step 3:Step 2 divided by 2

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given that BD is the median of ABD and that ABD is isosceles congruence postulate SSS can be used to prove which of the followin
Alja [10]

It is given in the question that

BD is the median. So it divides the opposite sides in two equal parts .

Therefore in triangles BAD and BCD,

AB and AC are congruent because of isosceles triangle.

AD and CD are congruent because of the median BD.

And BD and BD are congruent .

So the two triangles are congruent by SSS and the correct option is the first option .

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3 years ago
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Math question down below
mezya [45]

y=1 is the answer, there is no slope, so the formula y=mx+b turns into y=b, since 1 is the intercept 1 is b.

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3 years ago
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I suck at math and i really need help asap!
AlladinOne [14]

Answer:

2

Step-by-step explanation:

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4 years ago
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HELP ME I DONT KNOW HOW TO FIND THE PERIMETER
Phantasy [73]

Answer:

33.08 m

Step-by-step explanation:

angle of ∆ = 131.6 - 90 = 41.6

=> x² = 8²+3²-2(8)(3)cos 41.6°

= 64+9-48(0.75)

= 73 - 36

= 37

x = √37 = 6.08 m

perimeter = (3×8)+3+6.08 = 33.08 m

5 0
3 years ago
Please answer the following questions​
laila [671]

Answer:

4a) 110 square centimetres

4b) 127 square centimetres

6) 292 square centimetres

8) 800 tiles

Step-by-step explanation:

4. We need to find the area of the large rectangle and then deduct the area of the unshaded part:

a) The large rectangle has dimensions 12 cm by 15 cm. Its area is:

A = 12 * 15 = 180 square centimetres

The unshaded part has a length of 15 - (3 + 2) cm i.e. 10 cm and a width of 7 cm. Its area is:

a = 10 * 7 = 70 square centimetres

Therefore, the area of the shaded part is:

A - a = 180  - 70 = 110 square centimetres

b) The large rectangle has dimensions 13 cm by 11 cm. Its area is:

A = 13 * 11 = 143 square centimetres

The unshaded part has dimensions 8 cm by 2 cm. Its area is:

a = 8 * 2 = 16 square centimetres

Therefore, the area of the shaded part is:

A - a = 143 - 16 = 127 square centimetres

6. The background area of the space not covered by the photograph is the area of the frame minus the area of the photograph.

The frame has dimensions 24 cm by 18 cm. Therefore, its area is:

A = 24 * 18 = 432 square centimetres

The photograph has dimensions 14 cm by 10 cm. Therefore, its area is:

a = 14 * 10 = 140 square centimetres

Therefore, the background area of the space not covered by the photograph is:

A - a = 432 - 140 = 292 square centimetres

8) The floor has dimensions 8 m by 4 m. The area of the floor is:

A = 8 * 4 = 32 square centimetres

Each square tile has dimensions 20 cm by 20 cm. In metres, that is 0.2 m by 0.2 m. The area of each tile is:

a = 0.2 * 0.2 = 0.04 square metres

The number of tiles that are needed is the area of the floor divided by the area of each tile:

A / a = 32 / 0.04 = 800 tiles

4 0
4 years ago
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