given that BD is the median of ABD and that ABD is isosceles congruence postulate SSS can be used to prove which of the followin
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2 answers:
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Number of children attended is 1200 and number of adults attended is 1500
<h3><u>Solution:</u></h3>Given that,
Admission fee for each children = $ 1.50
Admission fee for each adult = $ 4.00
Let "c" be the number of children attended
Let "a" be the number of adults attended
Given that 2700 people enter and $7800 is collected
Number of children attended + number of adults attended = 2700
c + a = 2700 -------- eqn 1
Also given that $7800 is collected
Number of children attended x Admission fee for each children + number of adults attended x Admission fee for each adult = 7800
1.5c + 4a = 7800 -------- eqn 2
Let us solve eqn 1 and eqn 2 to find values of "a" and "c"
From eqn1,
a = 2700 - c ----- eqn 3
Substitute eqn 3 in eqn 2
1.5c + 4(2700 - c) = 7800
1.5c + 10800 - 4c = 7800
-2.5c = -3000
c = 1200
Therefore from eqn 3,
a = 2700 - 1200
a = 1500
Therefore number of children attended = c = 1200
number of adults attended = a = 1500
Answer:
We conclude that supermarket ketchup was not as good as the national brand ketchup.
Step-by-step explanation:
We are given the following in the question:
Sample size, n = 100
p = 69% = 0.69
Alpha, α = 0.05
Number of stating that the supermarket brand was as good as the national brand , x = 56
a) First, we design the null and the alternate hypothesis
This is a two-tailed test.
b) Formula:
Putting the values, we get,
Now, we calculate the p-value from the table.
P-value = 0.0049
c) Since the p-value is lower than the significance level, we fail to accept the null and reject it.
Thus, we conclude that supermarket ketchup was not as good as the national brand ketchup.
d) It need to be tested further whether the supermarket brand was worse than the national brand or better than the national brand.