Answer:
b. circle; 
Step-by-step explanation:
The given conic has equation;

We complete the square to obtain;

This is a circle with center;

This implies that;

When the circle is rotated through an angle of
,
The new center is obtained using;
and 
We plug in the given angle with x and y values to get;
and 
This gives us;

The equation of the rotated circle is;

Expand;

Multiply through by 4; to get

Write in general form;

Divide through by 2.

Convert to a fraction by placing the decimal number over a power of 10. So the awnser is 97/500
I hope I helped you
931 is the frst number and the rest ar decimals ie 931.857142.......
I can help with 3
Each side is different because the rectangle has opposite sides, so the equations should be different