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Alika [10]
3 years ago
15

Thomas is 4 years older than his brother william. in five years the sum of their age will be 24. how old is each boy?

Mathematics
1 answer:
Rasek [7]3 years ago
5 0
Let William be x years old.

Thomas = (4 + x) years

In five years,

William = (x + 5) years

Thomas = 4 + x + 5 = (9 + x) years

Given, in five years sum of their ages is 24.

x + 5 + 9 + x = 24

2x + 14 = 24

2x = 24 - 14 

2x = 10

x = \frac{10}{2}

x = 5

Hence, William is 5 years old and Thomas is 9 years old.
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Answer:

a rectangle is twice as long as it is wide . if both its dimensions are increased 4 m , its area is increaed by 88 m squared make a sketch and find its original dimensions of the original rectangle

Step-by-step explanation:

Let l = the original length of the original rectangle

Let w = the original width of the original rectangle

From the description of the problem, we can construct the following two equations

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Substitute equation #1 into equation #2

(2w+4)*(w+4)=(2w*w)+88

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collect like terms on the same side of the equation

2w^2+2w^2 +12w+16-88=0

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Since 4 is afactor of each term, divide both sides of the equation by 4

w^2+3w-18=0

The quadratic equation can be factored into (w+6)*(w-3)=0

Therefore w=-6 or w=3

w=-6 can be rejected because the length of a rectangle can't be negative so

w=3 and from equation #1 l=2*w=2*3=6

I hope that this helps. The difficult part of the problem probably was to construct equation #1 and to factor the equation after performing all of the arithmetic operations.

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