Let's plug in a few points to see which graph belongs to the function f(x) = 2x^2
Let's say x =0, let's find y!
2(0)^2 = 2(0) = 0
So one point on our line is (0.0)
Just finding this point right here eliminates 3 of the answer choices. Your answer is the graph that goes through the point (0,0)
For your added convenience, I have attached the graph. :)
Answer:

OR

Step-by-step explanation:
Hi there!
Point-slope form:
where <em>m</em> is the slope of the line and
is a given point
Given that the slope is -3/4, we can plug it into
as <em>m</em>:

We can also plug in the given point (1,2):

Slope-intercept form:
where <em>m</em> is the slope and <em>b</em> is the y-intercept (the value of y when the line crosses the y-axis)
To write the equation in slope-intercept form, isolate <em>y</em>:

I hope this helps!
Answer:
Find the value of what? Update the question and I will answer
Step-by-step explanation:
2x+1=27032
2x=27031
x=13515.5
2x+3
=2(13515.5)+3
=27034
Answer:
6
Step-by-step explanation: