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Answer:
The same 45.98 g of NaCl will be produced since 2 moles of Na will react with 2 moles of NaCl. Hence the stoichiometric coefficient will be in a ratio of 1:1
Answer:
V = 267.2 L
Explanation:
Given data:
Volume of balloon = ?
Mass of helium = 2.50 g
Temperature of gas = 180°C
Pressure = 0.87 atm
Solution:
Number of moles of helium:
Number of moles = mass/molar mass
Number of moles = 2.50 g/ 4 g/mol
Number of moles = 0.625 g
Volume of helium:
PV = nRT
R = general gas constant = 0.0821 atm.L/mol.K
0.87 atm× V = 0.625 mol × 0.0821 atm.L/mol.K×453 K
V = 232.45 atm.L /0.87 atm
V = 267.2 L
Answer:
Explanation:
THE QUESTION SHOULD BE
Write the equilibrium constant expression, Kc, for the following reaction: If either the numerator or denominator is 1, please enter 1 CaCO3(s).
CaCO3(s) <=> Ca2+(aq) + CO32-(aq)
Write the mathematical form of the concentration of the products, then divide it by the concentration of the reactants as follows
Kc =[Ca2+]^1 . [CO32-]^1 / [CaCO3]^1