3 years ago

How many grams are in 0.5 mols of Zn

Chemistry

1 answer:

anastassius [24]3 years ago

7 0

Answer:

32.69g

Explanation:

m=MM × n

m= 65.38×0.5

m=32.69g

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you ned to make an aqeous solution of .139M aluminum nitrate for an experiment in a lab, using 300. ml volumetric flask. how muc

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Answer:

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Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to use the definition of molarity to calculate the moles of aluminum nitrate as follows:

$M=\frac{n}{V}\\\\n=M*V\\\\n=0.139mol/L*0.300L=0.0417mol$

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Regards!

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