Answer:
105 ways
Step-by-step explanation:
Because the order of selection does not matter, we know that we will be using a combination instead of a permutation.
₁₅C₂ = 15! / (2! * 13!)
= 15 * 14 * ... * 2 * 1 / 2 * 1 * 13 * 12 * ... * 2 * 1
= 15 * 14 / 2 * 1 (The 13! cancels out)
= 105
105 ways, because the order of selection does not matter, we know that we will be using a combination instead of a permutation.
First add 11 then -69
b=7
2(3b-1)= 40
divide both sides by 2
3b-1 = 20
then add 1 to each side
3b = 21
then divide both sides by 3
b = 7
then check 2(3*7-1) = 40
h = -47
I hope this helps!
281
Therefore, the answer is the first choice.
