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tamaranim1 [39]
3 years ago
5

What is the magnitude of the final velocity of the combined cars?

Physics
1 answer:
Alinara [238K]3 years ago
7 0
It is the same if no external forces are added , that’s your answer.
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A 52 kg person is running 2.5 m/s. What is their momentum?
aivan3 [116]

Answer:

130kg/ms

Explanation:

  1. given data
  2. mass,52kg
  3. velocity,2.5m/s
  • momentum?
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6 0
3 years ago
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What are Kepler’s Laws of Planetary Motion? How can each one of them be applied to the 8 planets of the Solar System, using exam
faust18 [17]

Answer:

Explanation:

As per the Kepler's law of planetary motions :

1- The orbits are of elliptical shape having two foci and Sun is located on one foci.

2- The line segment that joins a planet and the Sun sweeps out equal are at equal interval of time.

3- The orbital period square is directly proportional to the cube of semi major axis of its orbit.

Kepler's law are applied on each of the planets of our solar system as the distance of the Sun from the planet is calculated through this.

For example : from Kepler's first law we can see the eccentricity of the Earth's orbit is 0.0167.

6 0
3 years ago
When the boy crashes his bumper car into the girl's bumper car, the momentum from his car is transferred to hers. What evidence
Darya [45]

Answer:

Where is the text?

Explanation:

If you refer to the short sentence you wrote as text, I believe the answer is probably the word "crashes" because it shows how the momentum was transferred.

8 0
3 years ago
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You are walking around your neighborhood and you see a child on top of a roof of a building kick a soccer ball. The soccer ball
const2013 [10]

Answer:

The building is 61.19 m tall, approximately.

Explanation:

From the parabollic movement trayectory equation,

y=H+\frac{v_{0y}}{v_x}x-\frac{1}{2v_x^2}gx^2,

where H is the initial height of the ball and v_{oy} and v_x the inital velocities in the vertical and horizontal direction, respectively; we have

H=y-\frac{v_{0y}}{v_x}x+\frac{1}{2v_x^2}gx^2.

In this case, the ball landed at the coordinates \left(x,y\right)=\left(61,0\right), so

H=0-\frac{17\sin\left(43\deg\right)}{17\cos\left(43\deg\right)}\times 61+\frac{1}{2\left(17\cos\left(43\deg\right)\right)^2}\times 9.81\times 61^2 \approx 61.19.

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3 years ago
What is the charge of the negative sphere
tatyana61 [14]

Answer:

electrons

Explanation:

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3 years ago
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