So, there should be two forces acting on the refrigerator: the applied force and the friction force.
The question mentioned that the friction force was set to zero, so the only effective force now would be the applied force.
We have an applied force of 400 N to the right, this means that:
<span>The magnitude of the net force is 400, directed to the right.</span>
Answer:
1.343 atm
Explanation:
The mass of water above 1 square meter of swimming pool bottom is ...
M = (3.5 m)·(1000 kg/m^3) = 3500 kg/m^2
Then the force exerted by the water on the pool bottom is ...
F = Mg = (3500 kg/m^2)(9.8 m/s^2) = 34300 N/m^2 = 34300 Pa
Compared with atmospheric pressure, this is ...
34,300/10^5 = 0.343 . . . . atmospheres
Added to the atmospheric pressure on the water's surface, the total pressure on the pool bottom is 1.343 atmospheres.
Answer:
a. 125 kJ
Explanation:
Her total energy is the same as the potential energy she had at the top of the hill:
PE = mgh
= (52 kg)(9.8 m/s^2)(245 m) = 124,852 J
≈ 125 kJ . . . . matches choice A
_____
After skiing down 112 m, some of her initial energy is converted to kinetic energy, and some remains as potential energy. We assume the ski slope is essentially frictionless, and air resistance is negligible.
Answer:
0,93 atm
Explanation:
For this we will use PV = nRT
P is what we want to find
V = 1 L
n =
= 0,038 moles
R = 0,082 
T = 25°C = 298,15 K
P * 1 = 0,038 *0,082 * 298,15
P = 0,93 atm
Answer: The pressure in a liquid is different at different depths. Pressure increases as the depth increases. The pressure in a liquid is due to the weight of the column of water above. The greater pressure at the bottom would give a greater 'force per unit area' on the wall.
Explanation: