A man lifts a 5 Newton bag of groceries
1 answer:
You might be interested in
Answer:
For the Carnot air conditioner working as a heat pump between 63 and 100°F , It would transfer 3.125 Joules of heat for each Joule of electric energy supplied.
Explanation:
The process described corresponds to a Carnot Heat Pump. A heat pump is a devices that moves heat from a low temperature source to a relative high temperature destination. <em>To accomplish this it requires to supply external work</em>.
For any heat pump, the coefficient of performance is a relationship between the heat that is moving to the work that is required to spend doing it<em>.</em>
For a Carnot Heat pump, its coefficient of performance is defined as:
Where:
- T is the temperature of each heat deposit.
- The subscript H refers to the high temperature sink(in this case the outdoors at 100°F)
- The subscript L refers to the low temperature source (the room at 63°F)
Then, for this Carnot heat pump:
So for each 3.125 Joules of heat to moved is is required to supply 1 Joule of work.
Answer:
Explanation:
Given:
time (t = 10.0 sec)
power = 150 Hp
We need to find the energy transformed by a 150 Hp engine in 10 s.
Solution:
First we convert 150 Hp in watt.
So, power (p = 111900 watt)
We know that, if we multiply power by time, we get energy transform by engine.
-----------(1)
Where:
P ⇒ power.
E ⇒ Energy.
t ⇒ time.
Substitute p = 111900 watt and t = 10 s in equation 1.
Therefore, a 150 Hp engine could transform 1,119,000 joules energy in 10 s.