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Greeley [361]
3 years ago
14

A man lifts a 5 Newton bag of groceries

Physics
1 answer:
kiruha [24]3 years ago
6 0

Answer:

5.5 J

Explanation:

W=F*D=5*1.1=5.5 J

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Un caballo parte del reposo y alcanza una velocidad de 15m/s en un tiempo de 8s. ¿ Cuál fue su aceleración y que distancia recor
Lemur [1.5K]

Answer: A 120 metros por segundo

Explanation: multiplicas la velocidad por el tiempo

7 0
3 years ago
Why does a skateboard coasting on a flat surface slow down and eventually comes to a stop
Maurinko [17]

It depends on what skateboard. It will stop mainly because some  skateboards need a hill or curvy platform to function.

5 0
4 years ago
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what factors are associated with the advanced performance of japanese students on standardized tests?
Anton [14]

Answer:

Explanation:

honestly

8 0
3 years ago
A Carnot air conditioner takes energy from the thermal energy of a room at 63°F and transfers it as heat to the outdoors, which
vodomira [7]

Answer:

For the Carnot air conditioner working as a heat pump between 63 and 100°F , It would transfer 3.125 Joules of heat for each Joule of electric energy supplied.

Explanation:

The process described corresponds to a Carnot Heat Pump. A heat pump is a devices that moves heat from a low temperature source to a relative high temperature destination. <em>To accomplish this it requires to supply external work</em>.

For any heat pump, the coefficient of performance is a relationship between the heat that is moving to the work that is required to spend doing it<em>.</em>

For a Carnot Heat pump, its coefficient of performance is defined as:

COP_{HP}=\frac{T_H}{T_H-T_L} Where:

  • T is the temperature of each heat deposit.
  • The subscript H refers to the high temperature sink(in this case the outdoors at 100°F)
  • The subscript L refers to the low temperature source (the room at 63°F)

Then, for this Carnot heat pump:

COP_{HP}=\frac{T_H}{T_H-T_L}=\frac{100°F}{100°F-63°F}=3.125

So for each 3.125 Joules of heat to moved is is required to supply 1 Joule of work.

3 0
3 years ago
One horsepower is a unit of power equal to 746 W. How much energy can a 150-horsepower engine transform in 10.0 s?
Lelu [443]

Answer:

E = 1119000\ joules

Explanation:

Given:

1\ Hp = 746\ watt

time (t = 10.0 sec)

power = 150 Hp

We need to find the energy transformed by a 150 Hp engine in 10 s.

Solution:

First we convert 150 Hp in watt.

1\ Hp = 746\ watt

150\ Hp = 150\times 746\ watt

150\ Hp = 111900\ watt

So, power (p = 111900 watt)

We know that, if we multiply power by time, we get energy transform by engine.

P = \frac{E}{t}

E = P\times t\ joule  -----------(1)

Where:

P ⇒ power.

E ⇒ Energy.

t ⇒ time.

Substitute p = 111900 watt and t = 10 s in equation 1.

E = 111900\times 10

E = 1119000\ joules

Therefore, a 150 Hp engine could transform 1,119,000 joules energy  in 10 s.

4 0
3 years ago
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