Answer:
it's the first option
Step-by-step explanation:
hope that help you
Sin2(x) +cos(x)=1
from the relation: (sin2(x) +cos2(x) =1 )
so , sin2(x)=1-cos2(x)
by subs. in the main eqn.
1-cos2(x) + cos(x) =1
by simplify the eqn.
cos(x) -cos2(x)=0
take cos(x) as a common factor
cos(x)* (1-cos(x))=0
then cos(x)=0 && cos(x)=1
cos(x)=0 if x= pi/2
& cos(x) = 1 if x = 0 , 2*pi
so the solution is x= {0,pi/2 , 2*pi}
The answer is b
hope this helps :)
Answer:
Option (d).
Step-by-step explanation:
Note: The base of log is missing in h(x).
Consider the given functions are
The function m(x) can be written as
...(1)
The translation is defined as
.... (2)
Where, a is horizontal shift and b is vertical shift.
If a>0, then the graph shifts a units left and if a<0, then the graph shifts a units right.
If b>0, then the graph shifts b units up and if b<0, then the graph shifts b units down.
On comparing (1) and (2), we get

Therefore, we have to translate each point of the graph of h(x) 3 units left to get the graph of m(x).
Hence, option (d) is correct.
Answer:
Their slopes are opposites