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3 years ago

Jan says that a rhombus is a parallelogram and that every parallelogram is also a rhombus. Is Jan correct?

Mathematics

1 answer:

Andreyy893 years ago

5 0

Answer:

Step-by-step explanation:

Not all parallelograms are rhombuses, some parallelograms include rectangles, squares, hexagons, etc.

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LiRa [457]

Answer:

variable c

Step-by-step explanation:

the reason is because to get the answer to variable t you need variable c and 1.06 while with c all you need is c. I think anyways

8 0

4 years ago

1. Solve the following simultaneous equations using the matrix method.

dmitriy555 [2]

(i) Use the formula for the determinant of a 2×2 matrix.

$\begin{vmatrix}a&b\\c&d\end{vmatrix} = ad-bc$

$\implies \det(A) = \begin{vmatrix}4 & -3 \\ 2 & 5\end{vmatrix} = 4\times5 - (-3)\times2 = \boxed{26}$

(ii) The adjugate matrix is the transpose of the cofactor matrix of A. (These days, the "adjoint" of a matrix X is more commonly used to refer to the conjugate transpose of X, which is not the same.)

The cofactor of the (i, j)-th entry of A is the determinant of the matrix you get after deleting the i-th row and j-th column of A, multiplied by $(-1)^{i+j}$ . If C is the cofactor matrix of A, then

$C = \begin{pmatrix}5&-2\\3&4\end{pmatrix}$

Then the adjugate of A is the transpose of C,

$\mathrm{adj}(A) = C^\top = \boxed{\begin{pmatrix}5&3\\-2&4\end{pmatrix}}$

(iii) The inverse of A is equal to 1/det(A) times the adjugate:

$A^{-1} = \dfrac1{\det(A)} \mathrm{adj}(A) = \boxed{\begin{pmatrix}\frac5{26}&\frac3{26}\\\\-\frac1{13}&\frac2{13}\end{pmatrix}}$

(iv) The system of equations translates to the matrix equation

$A\begin{pmatrix}x\\y\end{pmatrix}=\begin{pmatrix}6\\16\end{pmatrix}$

Multiplying both sides on the left by the inverse of A gives

$A^{-1}\left(A\begin{pmatrix}x\\y\end{pmatrix}\right)=A^{-1} \begin{pmatrix}6\\16\end{pmatrix}$

$\left(A^{-1}A\right)\begin{pmatrix}x\\y\end{pmatrix}=A^{-1} \begin{pmatrix}6\\16\end{pmatrix}$

$\begin{pmatrix}x\\y\end{pmatrix}=\begin{pmatrix}\frac5{26}&\frac3{26}\\\\-\frac1{13}&\frac2{13}\end{pmatrix} \begin{pmatrix}6\\16\end{pmatrix}$

$\begin{pmatrix}x\\y\end{pmatrix}=\boxed{\begin{pmatrix}3\\2\end{pmatrix}}$

4 0

2 years ago

Help please. I need the answers

Yuki888 [10]

Hey there!

1. Arc IJ = 62
1/2(360 - 2(78 + 40)) = 62

2. Arc WY = 103
50 + 53 = 103

3. Arc DEG = 204
70 + 77 + 57 = 204

4. Use pythagorean theorem
12.4^2 = x^2 + 11.5^2
x = 12.3

5. Use pythagorean theorem
x^2 = 5.2^2 + 8.4^2
x = 9.9

6. Use pythagorean theorem
18.1^2 = 10.1^2 + x^2
x = 15.1

7. Use the formula for the area of a circle
A = pi x (10^2)
A = 100pi
A = 314.2yd^2

8. Use the formula for the area of a circle
A = pi x (5.4^2)
A = 29.16pi
A = 91.6m^2

9. Use the formula for the circumference of a circle
C = 2 x pi x 4
C = 8pi
C = 25.1ft

10. Use the formula for the circumference of a circle
C = 2 x pi x 3
C = 6pi
C = 18.9yd

11. Use the standard equation of a circle
4 = (x - 15)^2 + (y - 8)^2

12. Use the standard equation of a circle
122 = (x + 1)^2 + (y - 3)^2

Hope this helps!! :)
If there's anything else that I can help you with, please let me know!

8 0

4 years ago

chau rented a truck for one day. There was a base fee of 20.99 and an additional fee of 94 cents per mile. He paid 294.53 when h

Llana [10]

Answer:

291 miles

Step-by-step explanation:

solve and simplify the equation 294.53=.94x+20.99

5 0

4 years ago

Read 2 more answers

Look at the picure then awser please!