Answer:
Alright, so we have to find the LCM of 2.75 and 3.5.
A good start would be to multiply them together to get 9.625, but we want a whole day!
This would be every 77 days :)
The question is incomplete, here is the complete question:
Recall that m(t) = m.(1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500 g sample of phosphorus-32 decays to 356 g over 7 days. Calculate the half life of the sample.
<u>Answer:</u> The half life of the sample of phosphorus-32 is 
<u>Step-by-step explanation:</u>
The equation used to calculate the half life of the sample is given as:

where,
m(t) = amount of sample after time 't' = 356 g
= initial amount of the sample = 500 g
t = time period = 7 days
h = half life of the sample = ?
Putting values in above equation, we get:

Hence, the half life of the sample of phosphorus-32 is 
31 seconds it will take to get around without it stopping
Answer:
C and E
Step-by-step explanation:
-2/3 = -0.66
so hence forth
2/3 = 0.66
- (2/3) = -0.66 and
2/-3 = -0.66