I think it is 9 1/2 feet.
Answer:
Step-by-step explanation:
Consider the given triangle ABC, we have AC = BC, AB = 6 in, CD ⊥ AB, and CD = 3 in. Using ΔCDB, we have
Therefore, (Given)
Now, Perimeter of an isosceles triangle is given By: 2a+b
⇒
which is the required perimeter of isosceles triangle.
<span>To solve this problem, what we have to do is to divide
the whole equation 4 x^4 – 2 x^3 – 6 x^2 + x – 5 with the equation 2 x^2 +
x – 1. Whatever remainder we get must be the value that we have to subtract from
the main equation 4 x^4 – 2 x^3 – 6 x^2 + x – 5 for it to be exactly divisible
by 2 x^2 + x – 1.</span>
By using any method, I used long division we get a
remainder of -6.
Therefore we have to subtract -6 from the main equation
which results in:
<span>4 x^4 – 2 x^3 – 6 x^2 + x – 5 – (-6) = 4 x^4 – 2 x^3 – 6 x^2
+ x + 1</span>
Answer:
Step-by-step explanation: