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vlabodo [156]
3 years ago
5

Pretty sure its 8 but i just wanna be sure...

Mathematics
2 answers:
Agata [3.3K]3 years ago
4 0

Answer:

Yup i'm pretty sure its 8 :D

Step-by-step explanation:

DochEvi [55]3 years ago
4 0

Answer:

yeah, basically certain it 8!!

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Choose the graph of the function f(x) = x - 2.
Gennadij [26K]

Answer:

The answer in the attached figure

Step-by-step explanation:

we have

f(x)=x-2

This is a linear equation

The slope is equal to m=1

The y-intercept is equal to the point (0,-2) ----> value of the function f(x) when the value of x is equal to zero

The x-intercept is equal to the point (2,0) ----> value of x when the value of the function is equal to zero

using a graphing tool

see the attached figure


4 0
3 years ago
Read 2 more answers
Change the following into mixed fraction 13/5​
Oduvanchick [21]

Answer:

2 3/5

Step-by-step explanation:

13/5​

5 goes into 13 2 time

2*5 =10

13-10 =3

There is 3 left over.  This goes over the denominator

2 3/5

7 0
3 years ago
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Which of the following did not occur during the reign of Diocletian? A. Church leaders were arrested. B. Christians were crucifi
MA_775_DIABLO [31]

Answer: B is the answer

Step-by-step explanation:

6 0
3 years ago
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I am a graph that records each piece of data above a number line
dolphi86 [110]
That type of graph is called a line plot
8 0
3 years ago
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Solve for x in the equation x2 - 4x-9 = 29.
erastova [34]

Answer:

x=2+\sqrt{21}\\\\x=2-\sqrt{21}

Step-by-step explanation:

One is given the following equation;

x^2-4x-9=29

The problem asks one to find the roots of the equation. The roots of a quadratic equation are the (x-coordinate) of the points where the graph of the equation intersects the x-axis. In essence, the zeros of the equation, these values can be found using the quadratic formula. In order to do this, one has to ensure that one side of the equation is solved for (0) and in standard form. This can be done with inverse operations;

x^2-4x-9=29

x^2-4x-38=0

This equation is now in standard form. The standard form of a quadratic equation complies with the following format;

ax^2+bx+c

The quadratic formula uses the coefficients of the quadratic equation to find the zeros this equation is as follows,

\frac{-b(+-)\sqrt{b^2-4ac}}{2a}

Substitute the coefficients of the given equation in and solve for the roots;

\frac{-(-4)(+-)\sqrt{(-4)^2-4(1)(-38)}}{2(1)}

Simplify,

\frac{-(-4)(+-)\sqrt{(-4)^2-4(1)(-38)}}{2(1)}\\\\=\frac{4(+-)\sqrt{16+152}}{2}\\\\=\frac{4(+-)\sqrt{168}}{2}\\\\=\frac{4(+-)2\sqrt{21}}{2}\\\\=2(+-)\sqrt{21}

Therefore, the following statement can be made;

x=2+\sqrt{21}\\\\x=2-\sqrt{21}

8 0
2 years ago
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