Given :
The half life of Carbon-14 , 
.
Trace amounts of Carbon-14 1/2408 remains.
To Find :
How old is the rock .
Solution :
Let , initial concentration of Carbon-14 is C .
Quantity remains , 
.
Rate constant is :
By first order equation :
![kt=-ln(\dfrac{[A_t]}{[A_o]})\\\\t=-\dfrac{ln(\dfrac{[A_t]}{[A_o]})}{k}\\\\t=-\dfrac{ln(\dfrac{[A_o]}{[A_o]\times 2408})}{1.2\times 10^{-4}}\ years\\\\t=-\dfrac{ln(\dfrac{1}{2408})}{1.2\times 10^{-4}}\ years\\\\t=64887.9\ years](https://tex.z-dn.net/?f=kt%3D-ln%28%5Cdfrac%7B%5BA_t%5D%7D%7B%5BA_o%5D%7D%29%5C%5C%5C%5Ct%3D-%5Cdfrac%7Bln%28%5Cdfrac%7B%5BA_t%5D%7D%7B%5BA_o%5D%7D%29%7D%7Bk%7D%5C%5C%5C%5Ct%3D-%5Cdfrac%7Bln%28%5Cdfrac%7B%5BA_o%5D%7D%7B%5BA_o%5D%5Ctimes%202408%7D%29%7D%7B1.2%5Ctimes%2010%5E%7B-4%7D%7D%5C%20years%5C%5C%5C%5Ct%3D-%5Cdfrac%7Bln%28%5Cdfrac%7B1%7D%7B2408%7D%29%7D%7B1.2%5Ctimes%2010%5E%7B-4%7D%7D%5C%20years%5C%5C%5C%5Ct%3D64887.9%5C%20years)
Therefore , the rock is 64887.9 years old .
Hence , this is the required solution .
I hope this helps! you just write the genotypes on top of a square and move them down. then you check the corresponding phenotypes and write your probabilities.
Primary . an oocyte does meiosis 2 when fertilized
Embryology provides evidence for evolution because during their development, many organisms look similar, suggesting that very different organisms may have a common ancestor.
Answer:
TCTAGGA
Explanation:
The deoxyribonucleic acid (DNA) molecule consists of two single-strands, which are composed of four different types of nucleotide bases: Adenine (A), Thymine (T), Guanine (G) and Cytosine (C). These two DNA strands run in an anti-parallel direction to each other. According to the base-pairing rules, Adenine always pairs with Thymine, while Guanine always pairs with Cytosine. In DNA, Thymine and Adenine form two hydrogen bonds between them, while Guanine and Cytosine form three hydrogen bonds between them.
