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Brums [2.3K]
4 years ago
11

I need the answers to these question (with steps)

Mathematics
1 answer:
Pie4 years ago
6 0

Answer:

SO the question ask to find the approximate distance in mile of the light calculated by an astronomer where as the given is a light year, so base on the data has given, the possible answer would be 5.7624*10^14. I hope you are satisfied with my answer and feel free to ask for more

Step-by-step explanation:

You might be interested in
Pls help <br> Thank you for your cooperation &lt;3
MAXImum [283]

Answer:

378 feet

Step-by-step explanation:

12 3/5 x 30 = 378

5 0
3 years ago
Read 2 more answers
What percent of 600 is 180
alexira [117]
\frac{180}{600}=\frac{30 \times 6}{100 \times 6}=\frac{30}{100}=30\%

180 is 30% of 600.
3 0
4 years ago
Read 2 more answers
3x-4 3x-8 solve for x
Law Incorporation [45]

Answer:

32

Step-by-step explanation:

(3x-4)+(3x-8)=180

6x-12=180

6x=192

X=32

3 0
3 years ago
a new car, originally worth $35,795, depreciates at a rate of 17% per year. The value of the car can be represented by the equat
Sergio [31]

We have been given that a new car, originally worth $35,795, depreciates at a rate of 17% per year. The value of the car can be represented by the equation y=35795(0.83)^x, where x represents the number of years since purchase and y represents the value (in dollars) of the car.

To find the value of car of after 5 years, we will substitute x=5 in our given equation as:

y=35795(0.83)^5

y=35795\cdot (0.3939040643)

y=14099.79598

Upon rounding to nearest tenth, we will get:

y\approx 14099.8

Therefore, the car will be worth $14,099.8 after 5 years it is first purchased.

Since $14,099.8 is less than original value of car, therefore, we know hat value of car is depreciating and $14,099.8 is correct answer.

We also know that an exponential decay function is in form y=a(1-r)^x, where,

y = Final value after t years,

a = Initial value,

r = Decay rate in decimal form,

x= Time.

17\%=\frac{17}{100}=0.17

y=35795(1-0.17)^x

y=35795(0.83)^x

8 0
3 years ago
1. For centuries, mathematicians believed that quadratic equations, like the one below, had no solutions and were not solvable.
7nadin3 [17]

Answer:

See below.

Step-by-step explanation:

(a) Because the solution led to a square root of a negative number:

x^2 -10x+40=0

x^2 - 10x = -40   Completing the square:

(x - 5)^2 - 25 = -40

(x - 5)^2 = -15

x =  5 +/-√(-15)

There is no real square root of -15.

(b) A solution was found by introducing the operator i which stands for the square root of -1.

So the solution is  

= 5 +/- √(15) i.

These are called complex roots.

(c) Substituting in the original equation:

x^2 - 10 + 40:

((5 + √(-15)i)^2 - 10(5 + √(-15)i) + 40

= 25 + 10√(-15)i - 15 - 50 - 10√(-15)i  + 40

=  25 - 15 - 50 + 40

= 0.   So this checks out.

Now substitute 5 - √(-15)i

= 25 - 10√(-15)i - 15 - 50 + 10√(-15)i  + 40

=  25 - 15 - 50 + 40

= 0.  This checks out also.

8 0
3 years ago
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