Because they usually are at the center of data.
Answer:
third answer choice: 11
Step-by-step explanation:
f(x) = 4x + 3. Now if we let x = 2, we get f(2) = 4(2) + 3 = 11.
This '11' becomes the input to function g:
g(x) = x - 2, so g(11) = 11 - 2, or 9.
Thus, g(f(x)) = 9
Answer:
4
Step-by-step explanation:
With either pass you have to add $20 per day, so you can ignore that
Assuming he goes "x" days to sky you can calculate the days he has to go to equal $300.
300 = 79x
x = 300/79 = 3.8 days
If he goes 4 days to sky it costs 316, so in that case its cheaper to buy the season pass
Answer:
1. 10n
2. 3x^2z^2
3. 2(9n^3 - 3n^2 + 3n - 1)
4. (Put the same thing)
5. There are no common factors so it is completely factored out.
Step-by-step explanation:
For 1, you gotta find the gcf of the numbers and the variables. So, the common factor of 90, 70, 70, and -80 is 10. Nothing else greater than 10 divides these numbers. For the variables, only "n" is the GCF, as there is one "n" and all the other numbers have n^2 and etc.
For 2, same thing, you have to find the gcf for the numbers and the variables.
3. same thing ;-; (gcf is 2 btw, nothing divides the variables because 2 has no "n".
4. theres nothing that divides the numbers or the variables. So, the gcf is just 1.
All the numbers present in cubical dice = 6
- ( 1 , 2 , 3 , 4 , 5 ,6 ) <u>Total Outcomes = 6</u>
<u>Probability = Favorable outcomes / Total number of outcomes </u>
- Probability that 5 will come in first throw :-
<u>Favorable Outcomes = 1 </u>
<u>Favorable Outcomes = 1 Probability = 1/6</u>
- Probability that an odd number will come in second throw :-
<u>Favorable Outcomes = 3</u>
<u>Probability = 3/6 ; 1/2</u>
