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3 years ago

You don't have to answer them all but help me out !!

Mathematics

1 answer:

Mandarinka [93]3 years ago

8 0

Answer:

1. 10n

2. 3x^2z^2

3. 2(9n^3 - 3n^2 + 3n - 1)

4. (Put the same thing)

5. There are no common factors so it is completely factored out.

Step-by-step explanation:

For 1, you gotta find the gcf of the numbers and the variables. So, the common factor of 90, 70, 70, and -80 is 10. Nothing else greater than 10 divides these numbers. For the variables, only "n" is the GCF, as there is one "n" and all the other numbers have n^2 and etc.

For 2, same thing, you have to find the gcf for the numbers and the variables.

3. same thing ;-; (gcf is 2 btw, nothing divides the variables because 2 has no "n".

4. theres nothing that divides the numbers or the variables. So, the gcf is just 1.

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Write an equation in slope intercept form of the line that passes through the given point and is paraell to the graph of the equ

Nostrana [21]

1.) x = -3...this is a vertical line with an undefined slope. A parallel line to a vertical line is also a vertical line. A vertical line is represented by x = a number....that number being the x coordinate of ur point(4,2).
so ur parallel line is : x = 4 <==
=================
2.) y = -3/2x + 6....slope here is -3/2. A parallel line will have the same slope.

y = mx + b
slope(m) = -3/2
(2,-1)...x = 2 and y = -1
now we sub into the formula and find b, the y int
-1 = -3/2(2) + b
-1 = -3 + b
-1 + 3 = b
2 = b
so ur parallel line is : y = -3/2x + 2 <==
===================
y = -x - 2....the slope here is -1. A parallel line will have the same slope

y = mx + b
slope(m) = -1
(2,-2)...x = 2 and y = -2
now we sub into the formula and find b, the y int
-2 = -1(2) + b
-2 = -2 + b
-2 + 2 = b
0 = b
so ur parallel equation is : y = -x + 0 which can be written as : y = -x <=

8 0

3 years ago

SEE IMAGE! Two lines below intersect to form four angles, as shown. The measure of angle 2 is 114°. What is the sum of the measu

o-na [289]

ANSWER:

Angles 2 and 4 are vertical angles, which means they have the same angle measure because they are opposite of each other. So angles 2 and 4 are both 114 so that makes 228. All of the angles have to make 360, so 360 - 228 = 132. Then, 132/2 because there are two angles. That makes 66. And angles 1 and 3 are also vertical angles so they are also the same

The answer is 132

8 0

3 years ago

One measure of an athlete’s ability is the height of his or her vertical leap. Many professional basketball players are known fo

almond37 [142]

Answer:

(1) P( $\bar X$ < 26 inches) = 0.0436

(2) P(27.5 inches < $\bar X$ < 28.5 inches) = 0.2812

Step-by-step explanation:

We are given that the mean vertical leap of all NBA players is 28 inches. Suppose the standard deviation is 7 inches and 36 NBA players are selected at random.

Firstly, Let $\bar X$ = mean vertical leap for the 36 players

Assuming the data follows normal distribution; so the z score probability distribution for sample mean is given by;

Z = $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\mu$ = population mean vertical leap = 28 inches

$\sigma$ = standard deviation = 7 inches

n = sample of NBA player = 36

(1) Probability that the mean vertical leap for the 36 players will be less than 26 inches is given by = P( $\bar X$ < 26 inches)

P( $\bar X$ < 26) = P( $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ < $\frac{26-28}{\frac{7}{\sqrt{36} } }$ ) = P(Z < -1.71) = 1 - P(Z $\leq$ 1.71)

= 1 - 0.95637 = 0.0436

(2) <em>Now, here sample of NBA players is 26 so n = 26.</em>

Probability that the mean vertical leap for the 26 players will be between 27.5 and 28.5 inches is given by = P(27.5 inches < $\bar X$ < 28.5 inches) = P( $\bar X$ < 28.5 inches) - P( $\bar X$ $\leq$ 27.5 inches)

P( $\bar X$ < 28.5) = P( $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ < $\frac{28.5-28}{\frac{7}{\sqrt{26} } }$ ) = P(Z < 0.36) = 0.64058 {using z table}

P( $\bar X$ $\leq$ 27.5) = P( $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ $\leq$ $\frac{27.5-28}{\frac{7}{\sqrt{26} } }$ ) = P(Z $\leq$ -0.36) = 1 - P(Z < 0.36)