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katovenus [111]
3 years ago
5

Question 2 What is the value of —2(5) + 3?

Mathematics
2 answers:
Marina CMI [18]3 years ago
7 0
Answer: -7

Explanation:

-2 x 5 = -10 because multiplying one negative and one positive number always equals a negative number

Add 3 to -10 and you get -7

Hope this helps!
Nat2105 [25]3 years ago
6 0
I think the answer is -7
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The volume of this cylinder with height four units is 36 3.14 cubic units
inessss [21]

Answer:

The area of the base is 8pi and the radius is 2sqrt(2)

Step-by-step explanation:

5 0
3 years ago
Drag each tile to the correct box. Not all tiles will be used.
katrin [286]

Answer+Step-by-step explanation:

f^{-1}\left( x\right)  =\frac{1}{7} x^{2}+3 \ ,\text{where}\ x\geq 0

7 0
2 years ago
Andrew plans to retire in 32 years. He plans to invest part of his retirement funds in stocks, so he seeks out information on pa
Debora [2.8K]

Answer:

a) 0.0885 = 8.85% probability that the mean annual return on common stocks over the next 40 years will exceed 13%.

b) 0.4129 = 41.29% probability that the mean return will be less than 8%

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean 8.7% and standard deviation 20.2%.

This means that \mu = 8.7, \sigma = 20.2

40 years:

This means that n = 40, s = \frac{20.2}{\sqrt{40}}

(a) What is the probability (assuming that the past pattern of variation continues) that the mean annual return on common stocks over the next 40 years will exceed 13%?

This is 1 subtracted by the pvalue of Z when X = 13. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{13 - 8.7}{\frac{20.2}{\sqrt{40}}}

Z = 1.35

Z = 1.35 has a pvalue of 0.9115

1 - 0.9115 = 0.0885

0.0885 = 8.85% probability that the mean annual return on common stocks over the next 40 years will exceed 13%.

(b) What is the probability that the mean return will be less than 8%?

This is the pvalue of Z when X = 8. So

Z = \frac{X - \mu}{s}

Z = \frac{8 - 8.7}{\frac{20.2}{\sqrt{40}}}

Z = -0.22

Z = -0.22 has a pvalue of 0.4129

0.4129 = 41.29% probability that the mean return will be less than 8%

8 0
3 years ago
Find the percent change to the nearest whole percent. from 45 feet to 95 feet.
VMariaS [17]

Answer:

211%

Step-by-step explanation:

To calculate the percentage change between these two numbers we need to divide the end result from the initial starting point. Once we do this we need to multiply the product by 100 to get the percentage value.

95 / 45 = 2.11111

2.11111 * 100 = 211.11%

Finally, we can see that the percentage change from 45 ft. to 95 ft. is 211.11%. If we round this to the nearest whole percent it would be a change of 211%

8 0
3 years ago
En una pension de perros hay tres perros que pesan 20kg 10kg y otro 5kg si se contempla que 70kg de alimento dura 2 meses¿que ca
aleksley [76]

Answer:

40kg

20kg

10kg

Step-by-step explanation:

The computation of the food each one is getting as follows

Total weights of all dogs

= 20 kg + 10 kg + 5kg

= 35 kg

And, the food is 70 kg

So, each one is getting

for 20 kg

= 70 ÷ 35 × 20

= 40 kg

For 10 kg

= 70 ÷ 35 × 10

= 20 kg

And, for 5 kg

= 70 ÷ 35 × 5

= 10 kg

7 0
2 years ago
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