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frozen [14]
3 years ago
15

A shopper bought shoes marked 40$the sales tax is5% how much is the sales tax

Mathematics
2 answers:
SashulF [63]3 years ago
7 0

Answer:

42$

Step-by-step explanation:

5/100 =x/40

x*100=5*40

x*100=200

200/100

x=2

2+40

42

irakobra [83]3 years ago
5 0

The sales tax is 2$ Hope this is the answer you're looking for.

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Brent has a collection of 84 Bobble Head trophies he needs to box up for the move to his new home. He can fit 7 trophies into on
Alina [70]

\displaystyle \frac{84\,\text{trophies}}{\left(\frac{7\,\text{trophies}}{\text{box}}\right)}=\frac{84}{7}\,\text{box}\\\\=12\,\text{box}

Brent will need 12 boxes.

7 0
2 years ago
Given the function f(x) = x^4 + 3x^3 - 2x^2 - 6x - 1, use intermediate theorem to decide which of the following intervals contai
marta [7]

f(x) = x^4 + 3x^3 - 2x^2 - 6x - 1

Lets check with every option

(a) [-4,-3]

We plug in -4  for x  and -3 for x

f(-4) = (-4)^4 + 3(-4)^3 - 2(-4)^2 - 6(-4) - 1= 55

f(-3) = (-3)^4 + 3(-3)^3 - 2(-3)^2 - 6(-3) - 1= -1

f(-4) is positive and f(-3) is negative. there is some value at x=c on the interval [-4,-3] where f(c)=0. so there exists atleast one zero on this interval.

(b) [-3,-2]

We plug in -3  for x  and -2 for x

f(-3) = (-3)^4 + 3(-3)^3 - 2(-3)^2 - 6(-3) - 1= -1

f(-2) = (-2)^4 + 3(-2)^3 - 2(-2)^2 - 6(-2) - 1= -5

f(-2) is negative and f(-3) is negative. there is no value at x=c on the interval [-3,-2] where f(c)=0.  

(c) [-2,-1]

We plug in -2  for x  and -1 for x

f(-2) = (-2)^4 + 3(-2)^3 - 2(-2)^2 - 6(-2) - 1= -5

f(-1) = (-1)^4 + 3(-1)^3 - 2(-1)^2 - 6(-1) - 1= 1

f(-2) is negative and f(-1) is positive. there is some value at x=c on the interval [-2,-1] where f(c)=0. so there exists atleast one zero on this interval.

(d) [-1,0]

We plug in -1  for x  and 0 for x

f(-1) = (-1)^4 + 3(-1)^3 - 2(-1)^2 - 6(-1) - 1= 1

f(0) = (0)^4 + 3(0)^3 - 2(0)^2 - 6(0) - 1= -1

f(-1) is positive and f(0) is negative. there is some value at x=c on the interval [-1,0] where f(c)=0. so there exists atleast one zero on this interval.

(e) [0,1]

We plug in 0  for x  and 1 for x

f(0) = (0)^4 + 3(0)^3 - 2(0)^2 - 6(0) - 1= -1

f(1) = (1)^4 + 3(1)^3 - 2(1)^2 - 6(1) - 1= -5

f(0) is negative and f(1) is negative. there is no value at x=c on the interval [0,1] where f(c)=0.  

(f) [1,2]

We plug in 1  for x  and 2 for x

f(1) = (1)^4 + 3(1)^3 - 2(1)^2 - 6(1) - 1= -5

f(2) = (2)^4 + 3(2)^3 - 2(2)^2 - 6(2) - 1= 19

f(-4) is positive and f(-3) is negative. there is some value at x=c on the interval [-4,-3] where f(c)=0. so there exists atleast one zero on this interval.

so answers are (a) [-4,-3], (c) [-2,-1],  (d) [-1,0], (f) [1,2]

8 0
3 years ago
Read 2 more answers
-<br> The expression x² - 5 is prime.<br> Is it true or false
lana [24]

Answer:

false

Step-by-step explanation:

X squared minus 5 is not necessarily prime

7 0
2 years ago
Can someone please help
leonid [27]

Answers:

  • Lateral Area = No lateral area (choice D)
  • Surface Area = 25.97 square inches (choice E)
  • Volume = 12.44 cubic inches (choice A)

============================================

Explanation:

Lateral area only applies to prisms and cylinders. Spheres do not have lateral sides, so there is no lateral area.

-----------------------

The radius is 1 & 7/16

Let's convert this to decimal form

1 & 7/16 = 1 + (7/16)

1 & 7/16 = 1 + 0.4375

1 & 7/16 = 1.4375

The radius is r = 1.4375 inches.

-----------------------

SA = Surface area the sphere

SA = 4*pi*r^2

SA = 4*pi*(1.4375)^2

SA = 25.9672267773281

SA = 25.97 square inches (choice E)

-----------------------

V = Volume of the sphere

V = (4/3)*pi*r^3

V = (4/3)*pi*(1.4375)^3

V = 12.4426294974698

V = 12.44 cubic inches (choice A)

8 0
3 years ago
If a box of 100 pencils<br> costs $4.25, what<br> would you expect to<br> pay for 224 pencils?
Serjik [45]

Answer:

$9.52

Step-by-step explanation:

4.25 divided by 100 gets you 0.0425 then multiply that number by 224

3 0
3 years ago
Read 2 more answers
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