All categories

2 years ago

Jane has a average score of 73% on three quizzes. What must she score on the next quiz to have an average of 78%?

Mathematics

1 answer:

Ket [755]2 years ago

4 0

Answer:

Step-by-step explanation:

The average is calculated as

average = $\frac{sum}{count}$

On 3 quizzes

$\frac{sum}{3}$ = 73 ( multiply both sides by 3 )

sum = 219

On 4 quizzes, letting x be the score on fourth test

$\frac{sum+x}{4}$ = 78 ( multiply both sides by 4 )

sum + x = 312 , that is

219 + x = 312 ( subtract 219 from both sides )

x = 93

She must score 93 on the next quiz

You might be interested in

Round 5294 to the nearest hundred

sleet_krkn [62]

It would be 5300 when rounded

5 0

2 years ago

F(x)=2^x evaluate f(5)

Helen [10]

Hey there!

To solve this, we will first replace x with 5 anytime we see it in the equation.

f(5) = 2^5

Now, we simplify 2^5.

The base is 2 and the exponent is 5 in this case.

The exponent is the number of times you multiply the base by itself. In oour case:

2 x 2 x 2 x 2 x 2 = 32

f(5) = 32

Hope this helps!

3 0

3 years ago

What is 0.83 in fraction form?

levacccp [35]

83/100 is 0.83 in fraction form

8 0

3 years ago

Read 2 more answers

Finding a polynomial of a given degree with given zeros

galben [10]

Since f(x) is a polynomial with 3rd degree, then it will have 3 roots (zeroes)

One of them is real and the other two are complex conjugate roots

Since the real root is 4, then

x = 4

Since the complex root is (1 - i), then

The other root will be the conjugate of it (1 + i)

x = (1 - i)

x = (1 + i)

To find f(x) we will multiply the three factors of it

We can get the factors from the zeroes

$x=4$

Subtract 4 from both sides

$\begin{gathered} x-4=4-4 \\ x-4=0 \end{gathered}$

The first factor is (x - 4)

$\begin{gathered} x=1-i \\ x-(1-i)=(1-i)-(1-i) \\ x-1+i=0 \end{gathered}$

The second factor is (x - 1 + i)

The third factor is (x - 1 - i)

$f(x)=(x-4)(x-1+i)(x-1-i)$

We will multiply them to find f(x)

$\begin{gathered} (x-1+i)(x-1-i)= \\ x^2-x-ix-x+1+i+ix-i-(i^2)= \\ x^2-2x+1-(-1)= \\ x^2-2x+1+1= \\ x^2-2x+2 \end{gathered}$

Multiply it by (x - 4)

$\begin{gathered} f(x)=(x-4)(x^2-2x+2) \\ f(x)=x^3-2x^2+2x-4x^2+8x-8 \\ f(x)=x^3-6x^2+10x-8 \end{gathered}$

The answer is

$f(x)=x^3-6x^2+10x-8$

5 0

11 months ago

Hey i need some help :)

melamori03 [73]

Answer:

[See Below]

Step-by-step explanation:

$\boxed{Hey~There!}$

__________________________________________________________

$\boxed{Solve~-3x$

Rearrange the equation by subtracting what is to the right of the greater than sign (≤, ≥) from both sides of the inequality:

$-3*x-(9)$

Pull out like factors:

$-3x - 9 = -3 * (x + 3)$

Divide both sides by $-3$ :

Remember to flip the inequality sign:

Subtract $3$ from both sides:

$x > -3$

$\boxed{The~answer~is: x > -3}$

$\boxed{The~answer~is: C}$

__________________________________________________________

$Hope~this~helps~Mate!\\-Your~Friendly~Answerer,~Shane$ ^-^

8 0

2 years ago