PLEASE HELP ASAP I always give brainliests!
1 answer:
first to find average age add all the ages divide by number of ages 4
5+4=9
9+6=15
15+39=54
54/4=13.5
For standard deviation find the mean/average
13.5
then subtract the mean from each number/age
5-13.5=-8.5
4-13.5=-9.5
6-13.5=-7.5
39-13.5=25.5
then square each number
-8.5^2=-72.25
-9.5^2=-90.25
-7.5^2=-56.25
25.5^2=650.25
then find the mean/average of the new numbers
-72.25+-90.25+-56.25+650.25=431.5
431.5/4=107.85
then take the square root of the new mean/average
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The correct question in the attached figure
Let
x-------------> <span>the number of granola bars
y-------------> the pounds of fruit
we know that
if 12 bars------------> cost $12
1 bars--------------> X
X=12/12---> x=$1
1 bar---------> cost $1
if 9 pounds of fruit----------> cost $36
1 pound-------------------> X
X=36/9--------> x=$4
1 pound -------> cost $4
</span><span>expression for the total cost=(1)*x+(4)*y----------> x+4y
</span><span>x=12
y=9
then
</span>the total cost=12+4*9----- $48
<span>an inequality that compares
the total cost with the amount you have to spend is
x+4y<=48
</span>
using a graph tool see the attached figure
<span>the inequality that models the number of granola bars you need to buy is
</span>
x<=12 the solution for the number of granola bars is the interval [0,12]
Let
x-------------> <span>the number of granola bars
y-------------> the pounds of fruit
we know that
if 12 bars------------> cost $12
1 bars--------------> X
X=12/12---> x=$1
1 bar---------> cost $1
if 9 pounds of fruit----------> cost $36
1 pound-------------------> X
X=36/9--------> x=$4
1 pound -------> cost $4
</span><span>expression for the total cost=(1)*x+(4)*y----------> x+4y
</span><span>x=12
y=9
then
</span>the total cost=12+4*9----- $48
<span>an inequality that compares
the total cost with the amount you have to spend is
x+4y<=48
</span>
using a graph tool see the attached figure
<span>the inequality that models the number of granola bars you need to buy is
</span>
x<=12 the solution for the number of granola bars is the interval [0,12]