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kumpel [21]
3 years ago
7

Calculate the pH of a solution if the concentration of hydroxide ions (OH-) is 3.6 x 10-11M?

Chemistry
1 answer:
baherus [9]3 years ago
7 0

Answer:

3.56

Explanation:

pH refers to a measure of hydrogen ion concentration. It measures acidity or alkalinity of a solution. It usually ranges from 0 to 14.

If pH of aqueous solutions at 25°C is less than 7 then they are acidic, while  aqueous solutions with a pH greater than 7 are alkaline.

Concentration of hydroxide ions = 3.6\times 10^{-11}

pH = -log \left ( 3.6\times 10^{-11} \right )=10.44

pOH = 14 - pH = 14 - 10.44 = 3.56

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Given that Δ H ∘ f [ Br ( g ) ] = 111.9 kJ ⋅ mol − 1 Δ H ∘ f [ C ( g ) ] = 716.7 kJ ⋅ mol − 1 Δ H ∘ f [ CBr 4 ( g ) ] = 29.4 kJ
JulsSmile [24]

Answer:

283.725 kJ ⋅ mol − 1

Explanation:

C(s) + 2Br2(g) ⇒ CBr4(g) , Δ H ∘ = 29.4 kJ ⋅ mol − 1

\frac{1}{2}Br2(g) ⇒ Br(g) ,  Δ H ∘ = 111.9 kJ ⋅ mol − 1

C(s) ⇒ C(g) ,  Δ H ∘ = 716.7 kJ ⋅ mol − 1

4*eqn(2) + eqn(3) ⇒ 2Br2(g) + C(s) ⇒ 4 Br(g) + C(g) , Δ H ∘ = 1164.3 kJ ⋅ mol − 1

eqn(1) - eqn(4) ⇒ 4 Br(g) + C(g) ⇒ CBr4(g) , Δ H ∘ = -1134.9 kJ ⋅ mol − 1

so,

   average bond enthalpy is \frac{1134.9}{4} = 283.725 kJ ⋅ mol − 1

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