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Vera_Pavlovna [14]
3 years ago
13

What is the momentum of a cat of mass 4 kg that is running south with a speed of 1.5 m/s?

Chemistry
2 answers:
arlik [135]3 years ago
8 0
The correct answer is b
Ulleksa [173]3 years ago
3 0

Answer:

option B is correct

Explanation:

momentum(p)=mv

mass= m=4 kg

velocity=v=1.5 m/s

P=4kg*1.5 m/s=6.0 kg.m/s

so option B is correct

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Answer:

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3 years ago
300 mL of 0.200 M Pb(NO3)2 is added to 200 mL of 0.0500 M NaCl(aq) at 25°C. Will a precipitate of PbCl2 form at 25 °C? Tip: You
Bas_tet [7]

Explanation:

It is given that volume of Pb(NO_{3})_{2} is 300 mL and molarity is 0.200 M.

Volume of NaCl is 200 mL and molarity is 0.050 M.

The chemical reaction will be as follows.

            PbCl_{2}(s) \rightleftharpoons Pb^{2+}(aq) + 2Cl^{-}(aq)

K_{sp} for PbCl_{2} is given as 1.7 \times 10^{-5}.

As, molarity is number of moles present in liter of solution.

Hence, moles of Pb^{2+}(aq) will be calculated as follows.

         moles of Pb^{2+}(aq) = 0.300 L \times 0.200 M

                                                = 0.06 mol

                      [Pb^{2+}] = \frac{0.06 mol}{0.5 L}

                                            = 0.120 M

Mole of Cl^{-}(aq) = 0.2 L \times 0.05 M  

                                  = 0.010 M

Now,   Q = [Pb^{2+}][Cl^{-}]^{2}

                  = 0.120 \times (0.010)^{2}

                  = 1.2 \times 10^{-5}    

As, Q < K_{sp} hence, there will be no formation of PbCl_{2} precipitate.

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Explanation:

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