Troposphere is the highest layer of the atmosphere and touches space
Startophere is where stratus clouds form up high in the sky
The Mesosphere is the third layer you need to know and it’s low density ...yo?
Thermosphere we’re getting closer and closer to earth
Exoshpere were airplanes are high, buckle up it’s time to fly
Answer:
19.5g is the theoretical yield of alum
Explanation:
Based on the balanced reaction, 4 moles of sulfuric acid produce 2 moles of alum. To solve this question we need to find the moles of H2SO4. With these moles we can find the moles of alum and its mass assuming all sulfuric acid reacts producing alum.
<em>Moles Sulfuric Acid:</em>
8.3mL = 0.0083L * (9.9mol/L) = 0.08217 moles sulfuric acid
<em>Moles Alum:</em>
0.08217 moles sulfuric acid * (2mol KAl(SO4)2•12H2O / 4mol H2SO4) =
0.041085 moles KAl(SO4)2•12H2O
<em>Mass Alum -Molar mass: 474.3884 g/mol-</em>
0.041085 moles KAl(SO4)2•12H2O * (474.3884 g/mol) =
<h3>19.5g is the theoretical yield of alum</h3>
Answer:
Q1. 0.82 mol
Q2. 9.20 g
Explanation:
Question 1
Step 1: Given and required data
- Mass of NaHCO₃ (m): 68.88 g
- Molar mass of NaHCO₃ (M): 84.01 g/mol
Step 2: Calculate the moles (n) corresponding to 68.88 g of NaHCO₃
We will use the following expression.
n = m/M
n = 68.88 g/(84.01 g/mol) = 0.82 mol
Question 2
Step 1: Given data
- Moles of NaOH (n): 0.23 mol
- Molar mass of NaOH (M): 40.00 g/mol
Step 2: Calculate the mass (m) corresponding to 0.23 moles of NaOH
We will use the following expression.
m = n × M
m = 0.23 mol × 40.00 g/mol = 9.20 g
Answer:
<h2>106.62 mL</h2>
Explanation:
The volume of a substance when given the density and mass can be found by using the formula

From the question
mass = 83.7 g
density = 0.785 g/mL
We have

We have the final answer as
<h3>106.62 mL</h3>
Hope this helps you