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mariarad [96]
2 years ago
9

Glass has a specific heat of 0.16 calories/gram°C.

Chemistry
2 answers:
Sloan [31]2 years ago
7 0
Calories heat added = Mass of glass times temp. increase times specific heat of glass

calories (small calories) = l.0 g x 20 degrees x .16 calories/gm/degree C = 3.2 calories
nignag [31]2 years ago
4 0

Answer:

3.2 calories

Explanation:

The state of aggregation of the glass does not change, as its temperature increases, it is a sensible heat, because it depends on its temperature.

The sensible heat formula is

Q= m.sh.T

sh= 0.16\frac{cal}{g C}

m= 1.0 g\\T= 20C

Q= 1.0 g.0.16\frac{cal}{gC} .20C\\ Q= 3.2 cal

<em>1.0 gram of glass will rise 20.0°C when 3.2 calories of heat are applied</em>

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A sailor on a trans-Pacific solo voyage notices one day that if he puts 375. mL of fresh water into a plastic cup fresh water we
ElenaW [278]

Answer:

Amount of salt dissolved in each liter of seawater = 40 g

Explanation:

According to Archimedes principle, a body will float in a fluid if the upthrust experienced by a body is equal to the to the weight of the body.

Also, the volume of seawater displaced equals the volume of freshwater in the cup.

From the above principle, since the freshwater and cup floats in the seawater, their combined weight equals the upthrust.

Therefore, mass of equal volume of displaced seawater = mass of freshwater + mass of cup

Mass of freshwater = density of freshwater * volume

density of freshwater = 1 g/mL; volume = 375 mL

mass of freshwater = 375 mL * 1 g/mL = 375 g

mass of seawater = 375 + 15 = 390 g

mass of salt in 375 mL seawater = mass of seawater - mass of freshwater

mass of salt = (390 - 375) g = 15 g

Since 15 g of salt are dissolved in 375 mL seawater, mass of salt in 1 L of seawater =(1000 mL/ 375) * 15g = 40 g

Therefore, amount of salt dissolved in each liter of seawater = 40 g

3 0
3 years ago
Graph the circle which is centered at (4,4)(4,4)left parenthesis, 4, comma, 4, right parenthesis and has a radius of 3 units.
OleMash [197]

Answer:

i dont know the answer sorry

7 0
3 years ago
A student takes a measured volume of 3.00 M HCl to prepare a 50.0 mL sample of 1.80 M HCI. What volume of 3.00 M HCI
frozen [14]

Answer:

30 mL VOLUME OF 3.0 M HCl SHOULD BE USED BY THE STUDENT TO MAKE A 1.80 M IN 50 mL OF HCl.

Explanation:

M1 = 3.00 M

M2 = 1.80 M

V2 = 50 .0 mL = 50 /1000 L = 0.05 L

V1 = unknown

In solving this question, we know that number of moles of a solution is equal to the molar concentration multiplied by the volume. To compare two samples, we equate both number of moles and substitute for the required component.

So we use the equation:

                                  M1 V1 = M2 V2

V1 = M2 V2 / M1

V2 = 1.80 * 0.05 / 3.0

V2 = 0.09 /3.0

V2 = 0.03 L or 30 mL

To prepare the sample of 1.80 M HCl in 50.0 mL from a 3.0 M HCl, 30 mL volume should be used.

5 0
3 years ago
Why is heat needed to get a reaction to occur
Ahat [919]

Answer:As temperature increases, reactions take place. Generally, higher temperatures mean faster reaction rates; as molecules move about more quickly, reactant molecules are more likely to interact, forming products.

Explanation:

4 0
3 years ago
Read 2 more answers
A 30ml sample of a liquid has a mass of 50 grams. What is the density of the liquid?
mash [69]

Answer:

<h2>Density = 1.67 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

Density =  \frac{mass}{volume}

From the question

mass = 50 g

volume = 30 mL

Substitute the values into the above formula and solve for the density

That's

Density =  \frac{50}{30}  \\  =  \frac{5}{3}  \\  = 1.66666...

Wr have the final answer as

<h3>Density = 1.67 g/mL</h3>

Hope this helps you

5 0
3 years ago
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