A move decimal behind the 7 ten places to the right since its positive
Answer:
Step-by-step explanation:
1k +9 > 30
1k +9 -9 > 30 -9
1k > 21
k > 21
Answer:

Step-by-step explanation:
We have:

And we want to find the value of x such that the expression is positive. So, we can write this as the following inequality:

Solve for the inequality. First, we can solve for the zeros like a normal quadratic. So, pretend the inequality is with an equal sign:

Zero Product Property:

On the left, subtract 5.
On the right, add 1.
So, our zeros are:

Since our inequality is a <em>greater than</em>, our answer is an "or" inequality with our answer being all the values to the <em>left</em> of our lesser zero and all the values to the <em>right </em>of our greater zero.
So, our solution is:

And we're done!
1st data set:
Minimum: 34
1st quartile: 35
Median: 36
3rd quartile: 37
Maximum: 38
Second data set:
Minimum: 20
1st quartile: 23
Median: 25
3rd quartile: 38
Maximum: 65
Graph
it based on the values of the 1st and 3rd quartile. If they are both
the same number away from the mean then they are symmetrical. Otherwise
they are not. In this case, the first one is similar and the second one
is not.
Please mark as brainiest!
Cheers
Answer:
Q1: p = - 33
Q2: d = - 99
Q3: t = - 13
Step-by-step explanation:
Q1: 
We solve this taking LCM.
We get: 


Q4: 
Again we proceed like Q1 by taking LCM.
We get: 



Q7: 5t + 12 = 4t - 1
We club the like terms on either side.



Hence, the answer.