A. The new molarity of the diluted solution is 0.047 M
B. The new molarity of the diluted solution is 0.188 M
C. The new molarity of the diluted solution is 4.4 M
D. The new molarity of the diluted solution is 1.28 M
A. How to determine the new molarity
- Volume of stock solution (V₁) = 26.6 mL
- Molarity of stock solution (M₁) = 0.127 M
- Volume of water = 45.4 mL
- Volume of diluted solution (V₂) = 26.6 + 45.4 = 72 mL
- Molarity of diluted solution (M₂) =?
M₁V₁ = M₂V₂
0.127 × 26.6 = M₂ × 72
Divide both side by 72
M₂ = (0.127 × 26.6) / 72
M₂ = 0.047 M
B. How to determine the new molarity
- Volume of stock solution (V₁) = 49.5 mL
- Molarity of stock solution (M₁) = 0.757 M
- Volume of water = 150 mL
- Volume of diluted solution (V₂) = 49.5 + 150 = 199.5 mL
- Molarity of diluted solution (M₂) =?
M₁V₁ = M₂V₂
0.757 ×49.5 = M₂ × 199.5
Divide both side by 199.5
M₂ = (0.757 × 49.5) / 199.5
M₂ = 0.188 M
C. How to determine the new molarity
- Volume of stock solution (V₁) = 102 mL
- Molarity of stock solution (M₁) = 25.8 M
- Volume of water = 500 mL
- Volume of diluted solution (V₂) = 102 + 500 = 602 mL
- Molarity of diluted solution (M₂) =?
M₁V₁ = M₂V₂
25.8 × 102 = M₂ × 602
Divide both side by 602
M₂ = (25.8 × 102) / 602
M₂ = 4.4 M
D. How to determine the new molarity
- Volume of stock solution (V₁) = 741 mL
- Molarity of stock solution (M₁) = 1.81 M
- Volume of water = 308 mL
- Volume of diluted solution (V₂) = 741 + 308 = 1049 mL
- Molarity of diluted solution (M₂) =?
M₁V₁ = M₂V₂
1.81 × 741 = M₂ × 1049
Divide both side by 1049
M₂ = (1.81 × 741) / 1049
M₂ = 1.28 M
Learn more about dilution:
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Answer:
=0.475M
Explanation:
Molarity=(moles of solute))/(litres of solution)
So, molarity in this question:
=(0.19 moles of sodium carbonate)/(0.4 L of solution)
=0.475M
~Hope this helps:)
C - rising and cooling, causing water vapor to condense
A)CH3OCH3 is the isomer of CH3CH2OH
ANSWER
Option A
EXPLANATION
Arrhenius defines an acid as a substance that will produce hydrogen ions as the only positive ion when dissolved in water.
He also defines a base as a substance that contains a hydroxide ion (OH^-).
Hence, the Arrhenius Model of acids and bases applies that is applied to the aqueous solution.
The correct answer is option A
