For a pendulum with a massless rope 'L' meters long, swinging through
a small arc, the period of the swing is
2 π √(L/g) seconds .
and it doesn't depend on the mass of the thing on the end of the rope ...
that could be a pebble or a bus.
For the girl on the 2.5-m rope,
Period = (2 π) √(2.5 / 9.8) = 3.17 seconds
Frequency = 1 / period = about <em> 0.315 Hz .</em>
<span>The length of the year is equivalent to the time it takes for the earth to go around the sun one time.</span>
Answer:
The SI unit of current is ampere which measures the flow of electric charge across a surface at the rate of one coulomb per second.
Answer:
a ) 2.368 rad/s
b) 3.617 rad/s
Explanation:
the minimum angular velocity that Prof. Stefanovic needs to spin the bucket for the water not to fall out can be determined by applying force equation in a circular path
i.e
------ equation (1)
where;
Also
since; that is the initial minimum angular velocity to keep the water in the bucket
Now; we can rewrite our equation as :
So; Given that:
The rope that is attached to the bucket is lm long and his arm is 75 cm long.
we have our radius r = 1 m + 75 cm
= ( 1 + 0.75 ) m
= 1.75 m
g = acceleration due to gravity = 9.81 m/s²
Replacing our values into equation (2) ; we have:
b) if he detaches the rope and spins the bucket by holding it with his hand ; then the radius = 0.75 m
∴