The correct answer is
"As the distance from the earth increases, the gravitational pull on the spaceship would decrease."
In fact, the gravitational force (attractive) exerted by the Earth on the spaceship is given by

where G is the gravitational constant, M the Earth's mass, m the mass of the spaceship and d the distance of the spaceship from the Earth. As we can see from the formula, as the distance d between the spaceship and the Earth increases, the gravitational force F decreases, so answer D) is the correct one.
Ok? I don’t know what you want me to do though
Answer:
S = 27500J / 308.15molK
Explanation:
Entropy measures the degree of disorganization of a system. It is measured in the entropy change that is equal to the heat exchanged divided by the temperature at which the process occurs.
S2-S1 = Q / T
S = entropy
Q = heat = 27.5 kJ / mol * 1000J / 1KJ = 27500J / mol
T = temperature = 35 + 273.15 = 308.15K
units = J / molK
S = 27500J / 308.15molK
I think the answer is b.boom