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Ostrovityanka [42]
3 years ago
7

Potassium ions (K+) move across a 7.0 -mm- thick cell membrane from the inside to the outside. The potential inside the cell is

−70.0 mV, and the potential outside is zero. What is the change in the electrical potential energy ΔU electric of the potassium ions as they move across the membrane?
Physics
1 answer:
Reil [10]3 years ago
7 0

Explanation:

Relation between potential energy and charge is as follows.

           U = qV

or,    \Delta U = q \times \Delta V

                   = 1.6 \times 10^{-19} \times 70 \times 10^{-3}

                   = 112 \times 10^{-22} J

or,                = 1.12 \times 10^{20} J

Therefore, we can conclude that change in the electrical potential energy \Delta U is 1.12 \times 10^{20} J.

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What is the magnitude of a the vertical electric field that will balance the weight of a plastic sphere of mass 2. 1 g that has
sladkih [1.3K]

The magnitude of a vertical electric field that will balance the weight of a plastic sphere of mass 2. 1 g that has been charged to -3. 0 NC is 6.86 × 10^{6} N/C.

An electric field is the physical field that surrounds electrically charged particles and exerts a force on all other charged particles in the field, either attracting or repelling them. It also refers to the physical field of a system of charged particles.

It is given that,

Mass of sphere, m = 2.1 g =0.0021kg

Charge,q = ₋3nC = ₋ 3 ₓ 10^{-9}

To balance the weight of a plastic sphere, we must determine the magnitude of the electric field. So,

ma= qE

a = g

E = \frac{mg}{q}

E = \frac{0.0021 * 9.8}{-3 * 10^{-9} }

E = 6860000 N/C

E = 6.86 × 10^{6} N/C

Hence, the magnitude of the electric field that balances its weight is 6.86 × 10^{6} N/C .

To know more about  electric field refer to:  brainly.com/question/8971780

#SPJ4

5 0
2 years ago
What is the Meaning of<br>Electromagnetism?​
ehidna [41]
The interaction of electric currents or fields and magnetic fields
3 0
4 years ago
(i) a force of 35.0 n is required to start a 6.0-kg box moving across a horizontal concrete floor, (a) what is the coefficient o
Serjik [45]

a. The force applied would be equal to the frictional force.

F = us Fn

where, F = applied force = 35 N, us = coeff of static friction, Fn = normal force = weight

 

35 N = us * (6 kg * 9.81 m/s^2)

us = 0.595

 

b. The force applied would now be the sum of the frictional force and force due to acceleration

F = uk Fn + m a

where, uk = coeff of kinetic friction

 

35 N = uk * (6 kg * 9.81 m/s^2) + (6kg * 0.60 m/s^2)

uk = 0.533

4 0
3 years ago
an object is moving with a speed of 35 m/s and has a kinetic energy of 1500 J, what is the mass of the object?
Elena-2011 [213]
You'd use the equation kinetic energy=mass*0.5*speed^2
So you'd rearrange this to get mass =kinetic energy /0.5 *speed^2
Which is mass= 1500J/0.5*35^2
=2.44897959183673469........kg
5 0
3 years ago
Two trucks with equal mass are attracted to each other with a gravitational force of 5.3 x 10 -4 N. The trucks are separated by
HACTEHA [7]

Answer:

7327 kg or 7.3 tons

Explanation:

We have Newton formula for attraction force between 2 objects with mass and a distance between them:

F_G = G\frac{M_1M_2}{R^2}

where G =6.67408*10^{-11} m^3/kgs^2 is the gravitational constant on Earth. M = M_1 = M_2 is the masses of the 2 objects. and R = 2.6m is the distance between them.

F_G = 5.3*10^{-4}N is the attraction force.

5.3*10^{-4} = 6.67408*10^{-11}\frac{M^2}{2.6^2}

7941265 = \frac{M^2}{2.6^2}

M^2 = 53682948.76

M = \sqrt{53682948.76} \approx 7327 kg or 7.3 tons

3 0
4 years ago
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