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3 years ago

Power = work+ time work time time work Fxd Ext Fxd

Physics

1 answer:

maw [93]3 years ago

4 0

Power is equal to the rate of energy usage, or work over time (W/t). It could also be consider Fd/t, since W=Fd.

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How does the constitution protect the rights of individuals against vivo

balandron [24]

The constitution protects the rights of people because in the constitution is the bill of rights. Which are admendments, which contain all or our rights.

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3 years ago

A 200N force pushes forward on the 20kg truck. The truck pulls two crates connected together by ropes, as shown. The gravitation

devlian [24]

Force on left crate, right crate and truck we need to draw here

First we will write the equation for left crate

$T_{left} = m*a$

$T_{left} = 20*a$

Now similarly for right crate

$T_{right} - T_{left} = 20*a$

now for truck

$F - T_{right} = 20*a$

Now we know that F = 200 N

$200 - T_{right} = 20*a$

now add all three equation

$T_{left} + T_{right} - T_{left} + 200 - T{right} = 20a + 20 a + 20a$

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now we will find all tension using this value of acceleration

$T_{left} = 20 * \frac{10}{3} = \frac{200}{3} N$

$T_{right} - \frac{200}{3} = 20*\frac{10}{3}$

$T_{right} = \frac{400}{3} N$

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3 years ago

Which of the following are heterogeneous mixtures (not homogeneous mixtures)?

BARSIC [14]

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Read more on Brainly.com - brainly.com/question/4731209#readmore

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3 years ago

Define the focus of a concave lens

Sophie [7]

Answer:

Principal focus of concave lens - 

★ The point at which rays parallel to principal axis coming from infinity appear to converge after being refracted from concave lens is called the principal focus of concave lens.

________________________

• Additional information - 

★ Principal focus - A number of rays parallel to the principal axis after reflection from a concave mirror meet at a point on the principal axis or appear to come from a point after reflection from a convex mirror on the principal axis. This is called principal focus.

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3 years ago

A 0.40 kg bead slides on a straight frictionless wire with a velocity of 3.50 cm/s to the right. The

tensa zangetsu [6.8K]

Answer:

Total momentum before collision

P1 =.4 * 3.5 = 1.4 ignoring units here

Total momentum after collision

P2 = .6 * V - .4 * .7 = .6 V - .28

.6 V = 1.4 + .28 momentum before = momentum after

V = 2.8 cm/sec

In 5 sec V moves 2.8 cm/sec * 5 sec = 14 cm

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3 years ago