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Katen [24]
3 years ago
6

What’s 2.95 as a percent

Mathematics
2 answers:
hichkok12 [17]3 years ago
4 0

Answer:

295%

Step-by-step explanation:

worty [1.4K]3 years ago
3 0

Answer:

295 percent

Step-by-step explanation:

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Use the drop-down menu to create true statements,
taurus [48]

Answer:

A) Vertical test

B) y=x

C) x

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5 0
3 years ago
Four students were scheduled to give book reports in 1 hour. After the first report, 2/3 hour remained. The next two reports too
Novosadov [1.4K]

Answer:1/4 hour remaining

Step-by-step explanation:

Presenter 1 - 1/3 hour

Presenter 2 - 1/6 hour

Presenter 3 - 1/4 hour

Convert to least common denominator of 12

4/12 + 2/12 + 3/12 = 9/12

12/12 - 9/12 = 3/12

Reduce 3/12 to get 1/4 hour remaining

3 0
3 years ago
Bagels: six in a bag Apples: eight in a bag Cookies: twelve in a box Juice Boxes: nine in a box Find the least number of package
morpeh [17]
Bagels 6x12=72
apples 8x9=72
cookies 12x6=72
juice 9x8=72

72/4 kids is 18 lunches
7 0
3 years ago
Side BC is 4 meters long. Side CD is twice the length of the side BC. What is the length of side LM. Explain your reasoning.
Misha Larkins [42]

Answer:

LM = 18

Step-by-step explanation:

BC = 4

CD is twice that, so CD is 8

Now, remembering that the area of ABCD = 32 and JKLM = 72, divide 72 by 32.

You get 2.25. This is how much bigger JKLM is than ABCD.

Using that, multiply the length of CD (which is 8) by 2.25 to get the length of LM.

You'll get 18.

Hope this helps!

4 0
2 years ago
Mr. Smith is flying his single-engine plane at an altitude of 2400 feet. He sees a cornfield at an angle of depression of 30º. W
Svet_ta [14]

Answer:

Height of the fighter plane =1.5km=1500 m

Speed of the fighter plane, v=720km/h=200 m/s

Let be the angle with the vertical so that the shell hits the plane. The situation is shown in the given figure.

Muzzle velocity of the gun, u=600 m/s

Time taken by the shell to hit the plane =t

Horizontal distance travelled by the shell =u

x

t

Distance travelled by the plane =vt

The shell hits the plane. Hence, these two distances must be equal.

u

x

t=vt

u Sin θ=v

Sin θ=v/u

=200/600=1/3=0.33

θ=Sin

−1

(0.33)=19.50

In order to avoid being hit by the shell, the pilot must fly the plane at an altitude (H) higher than the maximum height achieved by the shell for any angle of launch.

H

max

=u

2

sin

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(90−θ)/2g=600

2

/(2×10)=16km

4 0
3 years ago
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