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Shkiper50 [21]
4 years ago
8

What can be said about the radioactive decay of a single (not a large quantity) isotope?

Physics
2 answers:
ozzi4 years ago
5 0

Answer:

It is goin to have a long half life that is they have high stability.

Explanation:

The term radioactive decay can be defined as the spontaneous splitting or degradation of atoms of an isotope with unstable nucleus(parent nuclide) into a stable nucleus atoms(daughter nuclides). The following should be noted down for radioactive decay;

(1). Radioactive decay is a first order reaction.

(2). It is not affected by pressure.

(3). It is a spontaneous reaction..

The radioactive decay for a single (not a large quantity) isotope has a long half life because it will take more time for it to disintegrate into another nuclide

Elis [28]4 years ago
5 0

Answer:

Radioactive decay of single isotope is a spantenous decay of the nucleus of the atoms of that isotope. It is a degradation and changing process of the isotope into energy, and other forms of particles which are spintenously released from the decaying material. The radioactive decay of an isotope follows a decay constant by which its atoms reduces and has a half-life; a time through which half of its initial mass or atoms is/are lost.

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I don’t understand how to do this
anzhelika [568]

Explanation:

A) Use Hooke's law to find the spring constant.

F = kx

40 N = k (0.4 m)

k = 100 N/m

B) Period of a spring-mass system is:

T = 2π √(m / k)

T = 2π √(2.6 kg / 100 N/m)

T = 1 s

Frequency is the inverse of period.

f = 1 / T

f = 1 Hz

5 0
3 years ago
An airplane starts from rest and accelerates at a constant rate of 3.00 m/s2 for 30.0 s before leaving the ground. a. How far di
rosijanka [135]

The formula we can use in this case is:

d = v0t + 0.5 at^2

v = at + v0

where,

d = distance travelled

v0 = initial velocity = 0 since at rest

t = time travelled

a = acceleration

v = final velocity when it took off

 

a. d = 0 + 0.5 * 3 * 30^2

d = 1350 m

 

b. v = 3 * 30 + 0

<span>v = 90 m/s</span>

8 0
3 years ago
A child slides down a snow‑covered slope on a sled. At the top of the slope, her mother gives her a push to start her off with a
kirill [66]

Answer:

θ = 13.16 °

Explanation:

Lets take mass of child = m

Initial velocity ,u= 1.1 m/s

Final velocity ,v=3.7 m/s

d= 22.5 m

The force due to gravity along the incline plane = m g sinθ

The friction force = (m g)/5

Now from work power energy

We know that

work done by all forces = change in kinetic energy

( m g sinθ - (m g)/5 ) d = 1/2 m v² - 1/2 m u²

(2  g sinθ - ( 2 g)/5 ) d = v² -  u²

take g = 10 m/s²

(20 sinθ - ( 20)/5 ) 22.5 = 3.7² -  1.1²

20 sinθ - 4 =12.48/22.5

θ = 13.16 °

5 0
3 years ago
on the surface of planet x a body with a mass of 10 kilograms weighs 40 newtons. The magnitude of the acceleration due to gravit
tamaranim1 [39]
Based on the Newton's second law of motion, the value of the net force acting on the object is equal to the product of the mass and the acceleration due to gravity. If we let a be the acceleration due to gravity, the equation that would allow us to calculate it's value is,
      W = m x a
where W is weight, m is mass, and a is acceleration. Substituting the known values,
    40 kg m/s² = (10 kg) x a
Calculating for the value of a from the equation will give us an answer equal to 4. 
ANSWER: 4 m/s². 

6 0
3 years ago
Read 2 more answers
A chipmunk with a mass of 2 kg sits on a branch that is 10 m off the ground.
vlada-n [284]

I hope I'm not too late.

GPE = mass * gravity * height

GPE = 2 kg * 9.8 m/s * 10

GPE = 196 Joules

3 0
3 years ago
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