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svlad2 [7]
3 years ago
8

1.

Physics
1 answer:
irga5000 [103]3 years ago
6 0

Answer:

Explanation:

solution is found below

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During an auto accident, the vehicle's air bags deploy and slow down the passengers more gently than if they had hit the windshi
MArishka [77]

Answer:

0.3814128 m

Explanation:

t = Time taken = 36 ms

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration = 60g

g = Acceleration due to gravity = 9.81 m/s²

v=u+at\\\Rightarrow u=v-at\\\Rightarrow u=0-(-9.81\times 60)\times 36\times 10^{-3}\\\Rightarrow u=21.1896\ m/s

v^2-u^2=2as\\\Rightarrow s=\dfrac{v^2-u^2}{2a}\\\Rightarrow s=\dfrac{0^2-21.1896^2}{2\times -9.81\times 60}\\\Rightarrow s=0.3814128\ m

The distance the person traveled is 0.3814128 m

4 0
3 years ago
The wind is blowing horizontally at 30 m / s in a storm at P o , 20°C toward a wall, where it comes to a stop (stagnation) and l
aleksklad [387]

Answer:

 To=20.44 °C    

Explanation:

Given that

Velocity , v= 30 m/s

Temperature , T= 20°C

We know that specific heat capacity for air ,Cp=1.005 kJ/kg.K

By using energy conservation ,the stagnation temperature is given as

T_0=T+\dfrac{v^2}{2C_p}

Now by putting the values in the above equation we get

T_0=(20+273)+\dfrac{30^2}{2\times 1.005\times 1000}\ K

To= 293.44 K

To= 293.44 - 273 °C

To=20.44 °C

Therefore the stagnation temperature will be 20.44 °C.

3 0
3 years ago
An inventor claims to have developed a food freezer that, in steady-state conditions, requires a power input of 0.25 kW to extra
WARRIOR [948]

Answer:

The inventors  claim is not real

a)  No the the freezer cannot operate in such conditions

Explanation:

From the question we are told that

     The  power input is  P_i  = 0.25 kW  =  0.25 *10^{3} \ W

      The  rate of heat transfer J  =  3050 J/s

       The temperature of the freezer content is T = 270 \ K

       The  ambient temperature is  T_a  =  293 \ K

Generally the coefficient of performance of a refrigerator at idea conditions is mathematically represented as

      COP  =  \frac{T }{Ta - T}

substituting values

     COP  =  \frac{270 }{293 - 270}

     COP  =11.7

Generally the coefficient of performance of a refrigerator at real conditions is mathematically represented as

       COP  =  \frac{J}{P_i}

substituting values

       COP  =  \frac{3050}{0.25 *10^{3}}

       COP  = 12.2

Now given that the COP  of an ideal refrigerator is  less that that of a real refrigerator then the claims of the inventor is rejected

This is because the there are loss in the real refrigerator cycle that are suppose to reduce the COP compared to an ideal refrigerator cycle where there no loss that will reduce the COP

4 0
3 years ago
How do you solve this
Verdich [7]

Answer:

The answer is C

Explanation:

The radius is HALF of the diameter...so you would have to find a dividing "2".  :)

8 0
3 years ago
Read 2 more answers
Suppose Earth's gravitational force were decreased by half. How would this change affect a game of basketball? Write a paragraph
viktelen [127]
They would be able to jump higher with less effort the ball would weigh less meaning it could be dribbled with little to no effort there would also be the fact that your running would be effected.your legs would come off the ground if only for an inch or two allowing you to travel faster but with less control
5 0
3 years ago
Read 2 more answers
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