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svlad2 [7]
3 years ago
8

1.

Physics
1 answer:
irga5000 [103]3 years ago
6 0

Answer:

Explanation:

solution is found below

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PLEASE HELP ME WITH MY HOMEWORK!!!!!
IgorC [24]

Known :

l = 7 cm

w = 4 cm

Asked :

h = ...?

Answer :

V = B triangle × h (long)

35 = ½ × 4 × h × 7

35 = ½ × 28 × h

35 = 14 h

h = 35 ÷ 14

h = 2,5 cm

Sorry if I am wrong, I only study

5 0
3 years ago
Which situation is contrary to Newton’s first law of motion?
Bond [772]

Answer:

An object at rest stays at rest as long as unbalanced forces act on it.

Explanation:

Inertia can be defined as the tendency of an object or a body to continue in its state of motion or remain at rest unless acted upon by an external force.

In physics, Sir Isaac Newton's First Law of Motion is known as Law of Inertia and it states that, an object or a physical body in motion will continue in its state of motion at continuous velocity (the same speed and direction) or, if at rest, will remain at rest unless acted upon by an external force.

The inertia of a physical object such as a truck is greatly dependent or influenced by its mass; the higher the quantity of matter in a truck, the greater will be its tendency to continuously remain at rest.

Hence, the situation which is contrary to Newton’s first law of motion is that, an object at rest stays at rest as long as unbalanced forces act on it.

According to Newton’s first law of motion, an object at rest stays at rest as long as unbalanced forces do not act on it.

4 0
2 years ago
A force of 14 lb is required to hold a spring stretched 4 in. beyond its natural length. How much work W is done in stretching i
enyata [817]

Answer:

W = 19.8 J

Explanation:

14 lb force is required to stretch the spring by 4 inch distance

So we have

F = 14 lbf

F = 6.35 \times 9.8 N

F = 62.3 N

stretch in the spring is given as

x = 4 in = 0.1016 m

now we will have

F = kx

62.3 = k(0.1016)

k = 613.125 N/m

Now we need to find the work to stretch it by x = 10 in = 0.254 m

so we have

W = \frac{1}{2}kx^2

W = \frac{1}{2}(613.125)(0.254)^2

W = 19.8 J

7 0
3 years ago
If the pressure acting on a given sample of an ideal gas at constant temperature is tripled, what happens to the volume of the g
oee [108]

Answer:

Explanation:

According to Boyle's law  for constant temperature of gas Pressure is inversely proportional to the volume of gas.

PV=nRT

PV=constant

P\propto \frac{1}{V}

if Pressure is tripled then

P\times V_1=3P\times V_2

V_2=\frac{V_1}{3}

Volume becomes one-third of original volume          

7 0
3 years ago
A wall with a surface area of 10 m2 is 2.5 cm thick. The inner surface temperature of the wall is 4150C, but the outer surface i
klio [65]

Answer:

650.65 K or 377.5°C

Explanation:

Area = A = 10 m²

Thickness of wall = L = 2.5 cm = 2.5×10⁻² m

Inner surface temperature of wall = T_i = 415°C = 688.15 K

Outer surface temperature of wall = T_o

Heat loss through the wall = 3 kW = 3×10³ W

Thermal conductivity of wall = k = 0.2 W/m K

Assumptions made here as follows

  1. There is not heat generation in the wall itself
  2. The heat conduction is one dimensional
  3. Heat flow follows steady state
  4. The material has same properties in all directions i.e., it is homogeneous.

Considering the above assumptions we use the following formula

Q=\frac {T_i-T_o}{\frac{L}{kA}}\\\Rightarrow T_o=T_i-\frac {QL}{kA}\\\Rightarrow T_o=688.15-\frac {3\times 10^{3}\times 2.5\times 10^{-2}}{0.2\times 10}\\\Rightarrow T_o=650.65~K

∴ The temperature of the outer surface of the wall is 650.65 K or 377.5°C

5 0
3 years ago
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