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Xelga [282]
3 years ago
8

What is the value of b?​

Mathematics
2 answers:
koban [17]3 years ago
8 0

Answer:

b=24

Step-by-step explanation:

VT^2 + (2b)^2 = 67^2

VT^2 + (b+24)^2 = 67^2

-> (2b)^2 = (b+24)^2

-> 2b = b+ 24

-> b = 24

Molodets [167]3 years ago
7 0
B= 24
The work is on the other guys answer
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a certain triangle has a 30 degree angle and a 60 degree angle which must be true statement about the triangle
aksik [14]

Answer:

The final degree is 90

Step-by-step explanation:

Because every triangle equals up to 180 degrees.

6 0
3 years ago
How do I solve Cos-1(0.839) step by step?
Gelneren [198K]

Answer:

32.965°

Explanation:

To solve the expression we need to use the calculator, so:

\text{cos}^{-1}(0.839)=32.965

Therefore, the answer is 32.965°

5 0
1 year ago
The quotient of two numbers is
melomori [17]

Answer:

x = - 104, y = - 130

Step-by-step explanation:

the quotient of the 2 numbers is

\frac{x+26}{x} = \frac{4}{5} ( cross- multiply )

5(x + 26) = 4x

5x + 130 = 4x ( subtract 4x from both sides )

x + 130 = 0 ( subtract 130 from both sides )

x = - 130

First number is - 130 + 26 = - 104

second number is - 130

6 0
3 years ago
Name the property for 5*(12*x)=(5*12)*x
julsineya [31]

Answer:

wdym like distributive property or um all real numbers

Step-by-step explanation:

5 0
3 years ago
Someone ans plz
alexira [117]

The GCF is mn^{4} p^{3}

Explanation:

The GCF or greatest common factor is the factorization of two or more numbers to determine the greatest number that they have common.

The given terms are m^{7} n^{4} p^{3} and m n^{12} p^{5}

To determine the gcf of these two terms, let us find the greatest number that they have in common.

Comparing the powers of m from both the terms, we have,

g c f\left(m^{7}, m\right)=m

Similarly, comparing the powers of n from both the terms, we have,

g c f\left(n^{4}, n^{12}\right)=n^{4}

Also, comparing the powers of p from both the terms, we have,

g c f\left(p^{3}, p^{5}\right)=p^{3}

Thus, the GCF of the terms m^{7} n^{4} p^{3} and m n^{12} p^{5} is mn^{4} p^{3}

8 0
3 years ago
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