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Mariulka [41]
3 years ago
7

1. Jayron worked for 7.5 hours and got paid $63.75. How much does Jayron

Mathematics
2 answers:
Kazeer [188]3 years ago
6 0
The correct answer : $8.50 / 1 hour
denpristay [2]3 years ago
6 0

Answer:

$8.50/ 1 hour

Step By Step Explanation:

To find how much someone makes per hour, you have to divide how much money they made by how long it took them to make that money.

Therefore,

If Jayron makes $63.75 after working for 7.5 hours, to find how much he makes per hour you would have to divide 63.75 by 7.5, which is 8.5.

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Bob and James are finishing the roof of a house. Working alone, Bob can shingle the roof in 14 hours. James can shingle the same
Snowcat [4.5K]

we know that Bob can do the whole job in 14 hours, how much of the work has he done in 1 hour only?  well since he can do the whole lot in 14 hours in 1 hour he has only done 1/14 th of the job.

we know that James can do it in 18 hours, a bit slower, so in 1 hour he has done only 1/18 th of the job.

let's say it takes both of them working together say "t" hours, so in 1 hour Bob has done (1/14) of the work whilst James has done (1/18) of the work, the whole work being t/t or 1 whole, so for just one hour that'd 1/t done by both Bob and James.

\bf \stackrel{Bob}{\cfrac{1}{14}}~~+~~\stackrel{James}{\cfrac{1}{18}}~~=~~\stackrel{total~for~1~hour}{\cfrac{1}{t}} \\\\\\ \stackrel{\textit{using an LCD of 126}}{\cfrac{9+7}{126}=\cfrac{1}{t}}\implies \cfrac{16}{126}=\cfrac{1}{t}\implies 16t=126\implies t=\cfrac{126}{16} \\\\\\ \stackrel{\textit{7 hrs, 52 minutes and 30 seconds}}{t=\cfrac{63}{8}\implies t=7\frac{7}{8}}\implies \stackrel{\textit{rounded up}}{t=7.88}

7 0
3 years ago
What is 3 3/5 ÷ 1 4/5 =
Marysya12 [62]

Answer:

2

Step-by-step explanation:

3 3/5 : 1 4/5= 2/1 = 2

8 0
3 years ago
Read 2 more answers
There are big spenders among University of Alabama football season ticket holders. This data set Roll Tide!! shows the dollar am
Bas_tet [7]

Using the z-distribution, as we have a proportion, the 95% confidence interval is (0.2316, 0.3112).

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which:

  • \pi is the sample proportion.
  • z is the critical value.
  • n is the sample size.

In this problem, we have a 95% confidence level, hence\alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so the critical value is z = 1.96.

We also consider that 130 out of the 479 season ticket holders spent $1000 or more at the previous two home football games, hence:

n = 479, \pi = \frac{130}{479} = 0.2714

Hence the bounds of the interval are found as follows:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2714 - 1.96\sqrt{\frac{0.2714(0.7286)}{479}} = 0.2316

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2714 + 1.96\sqrt{\frac{0.2714(0.7286)}{479}} = 0.3112

The 95% confidence interval is (0.2316, 0.3112).

More can be learned about the z-distribution at brainly.com/question/25890103

7 0
2 years ago
.I want a way to solve this question​
Verdich [7]

Check the picture below.

so then γ ≈ 180 - 69 - 43, γ ≈ 68.

8 0
2 years ago
Point M is the midpoint of AB. The coordinates of point A are (−7, 1) and the coordinates of M are (−2, 2). What are the coordin
notka56 [123]

Answer:

\huge{\boxed{\sf{ ( 3 , 3 ) }}}

Step-by-step explanation:

Co-ordinates of point A = ( -7 , 1 )

Co-ordinates of point M = ( -2 , 2 )

Let the co-ordinates of point B be ( x , y )

A ( -7 , 1 ) \longrightarrow ( x1 , y1 )

B ( x , y ) \longrightarrow ( x2 , y2 )

Now,

Midpoint = (\frac{x1 + x2}{2}  , \frac{y1 + y2}{2} )

⇒( -2 , 2 ) = ( \frac{-7 + x}{2}  , \frac{1 + y}{2} )

Finding the value of x :                    

⇒-2 = \frac{-7 + x}{2}

Do cross multiplication                

⇒-4 = -7 + x

⇒-7 + x = -4

⇒x = -4 + 7

⇒x = 3

Now, finding the value of y

⇒2 = \frac{1+y}{2}

Do cross multiplication

⇒4 = 1+y

⇒1+y = 4

⇒y = 4 - 1

⇒y = 3

Hence, The co-ordinates of point B = ( 3 , 3 )

Hope I helped!

Best regards!

~\text{ TheAnimeGirl}

4 0
3 years ago
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