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Sphinxa [80]
3 years ago
7

A ball is thrown vertically downward with an initial speed of 12.0 m/s from a height of 10.0 m above the ground. Ignoring air re

sistance, what is the speed of the ball when it reaches the ground?
(A) 18.5 m/s
(B) 14.6 m/s
(C) 14.0 m/s
(D) 12.8 m/s
(E) 12.0 m/s
Can you just take a picture of your work clearly because I have to show work. Thanks.
Physics
1 answer:
natita [175]3 years ago
8 0

Answer:

18.5 m/s

Explanation:

Take down to be positive.

Given:

Δy = 10.0 m

v₀ = 12.0 m/s

a = 9.8 m/s²

Find: v

v² = v₀² + 2aΔy

v² = (12.0 m/s)² + 2 (10 m/s²) (10.0 m)

v = 18.5 m/s

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The practice of science can answer only scientific questions. And scientific
iragen [17]

Evidence might be used to demonstrate their falsity. must apply to all potential solutions to a scientific topic.Option A is correct.

<h3>What is a Scientific hypothesis?</h3>

A scientific hypothesis is the main element in the scientific method and experiment.

It is said that a hypothesis is a scientific hypothesis. The majority must agree on it, or it must be done after thorough experimentation.

Only scientific inquiries can have their answers provided by scientific endeavor. Scientific concerns have an impact on the research's design as well.

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A rope is vibrated so that transverse waves propagate down it. if the distance between crests is 0.5 m and a new crest reaches t
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7 0
4 years ago
Calculate the ionization potential for C+5 ( 5 electrons removed for the C atom) and in addition compute the wavelength of the t
sveta [45]

Answer:

Ionization potential of C⁺⁵ is 489.6 eV.

Wavelength of the transition from n=3 to n=2 is 1.83 x 10⁻⁸ m.

Explanation:

The ionization potential of hydrogen like atoms is given by the relation :

E = \frac{13.6Z^{2} }{n^{2} } eV     .....(1)

Here <em>E</em> is ionization potential, <em>Z</em> is atomic number and <em>n</em> is the principal quantum number which represents the state of the atom.

In this problem, the ionization potential of Carbon atom is to determine.

So, substitute 6 for <em>Z</em> and 1 for <em>n</em> in the equation (1).

E = \frac{13.6\times(6)^{2} }{1^{2} }

<em> E = </em>489.6 eV

The wavelength (λ)  of the photon due to the transition of electrons in Hydrogen like atom is given by the relation :

\frac{1}{\lambda} =RZ^{2}[\frac{1}{n_{1} ^{2}}-\frac{1}{n_{2} ^{2} }]     ......(2)

R is Rydberg constant, n₁ and n₂ are the transition states of the atom.

Substitute 6 for Z, 2 for n₁, 3 for n₂ and 1.09 x 10⁷ m⁻¹ for R in equation (2).

\frac{1}{\lambda} =1.09\times10^{7} \times6^{2}[\frac{1}{2 ^{2}}-\frac{1}{3 ^{2} }]

\frac{1}{\lambda}  = 5.45 x 10⁷

λ = 1.83 x 10⁻⁸ m

7 0
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The heat of fusion must be approx from 0 to infinity
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