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Licemer1 [7]
3 years ago
15

Which of the following words is an example of an interjection?

Physics
2 answers:
Nata [24]3 years ago
5 0
The answer is d. Oops
4vir4ik [10]3 years ago
3 0
An interjection is an abrupt remark so the answer is definitely D.) Oops
hope that helps:) <span />
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Little Tammy lines up to tackle Jackson to (unsuccessfully) prove the law of conservation of momentum. Tammy’s mass is 34.0 kg a
VikaD [51]

Answer: greater but no freaking clue How to figure it out

Explanation:

7 0
4 years ago
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A rocket traveling at 80 m/s is accelerated uniformly to 152 m/s over a 18 s interval. What is its displacement during this time
IgorLugansk [536]

Recall that with constant acceleration,

x_f-x_i=\dfrac{v_i+v_f}2t

where x_f-x_i is the rocket's displacment, v_i is its initial velocity, v_f its final velocity, and t is time. So

x_f-x_i=\dfrac{80\frac{\mathrm m}{\mathrm s}+152\,\frac{\mathrm m}{\mathrm s}}2(18\,\mathrm s)=2088\,\mathrm m

or just 2100 m if taking significant digits into account.

8 0
3 years ago
A gas is compressed from 600cm3 to 200cm3 at a constant pressure of 450kPa . At the same time, 100J of heat energy is transferre
Paraphin [41]

Answer: 80J

Explanation:

According to the first principle of thermodynamics:  

<em>"Energy is not created, nor destroyed, but it is conserved."  </em>

Then this priciple (also called Law) relates the work and the transferred heat exchanged in a system through the internal energy U, which is neither created nor destroyed, it is only transformed. So, in this especific case of the compressed gas:

\Delta U=Q+W  (1)

Where:

\Delta U is the variation in the internal (thermal) energy of the system (the value we want to find)

Q=-100J is the heat transferred out of the gas (that is why it is negative)

W is the work is done on the gas (as the gas is compressed, the work done on the gas must be considered positive )

On the other hand, the work done on the gas is given by:

W=-P \Delta V  (2)

Where:

P=450kPa=450(10)^{3}Pa is the constant pressure of the gas

\Delta V=V_{f}-V_{i} is the variation in volume of the gas

In this case the initial volume is V_{i}=600{cm}^{3}=600(10)^{-6}m^{3} and the final volume is V_{f}=200{cm}^{3}=200(10)^{-6}m^{3}.

This means:

\Delta V=200(10)^{-6}m^{3}-600(10)^{-6}m^{3}=-400(10)^{-6}m^{3}  (3)

Substituting (3) in (2):

W=-450(10)^{3}Pa(-400(10)^{-6}m^{3})  (4)

W=180J  (5)

Substituting (5) in (1):

\Delta U=-100J+180J  (6)

Finally:

\Delta U=80J  This is the change in thermal energy in the compression process.

8 0
4 years ago
A sample of a gas in a rigid container has an initial pressure of 1.049 kPa and an initial temperature of 7.39 K. The temperatur
Setler79 [48]

Answer: 4.358 kPa

Explanation:

The gas is contained within a rigid container, so the volume of the gas is constant. Therefore, we can use Gay-Lussac's law, which states that:

"for a gas kept at constant volume, the pressure and the absolute temperature are directly proportional"

In formulas:

\frac{P_1}{T_1}=\frac{P_2}{T_2}

where:

P_1 = 1.049 kPa is the initial pressure

T_1 = 7.39 K is the initial temperature

P_2 is the final pressure

T_2 = 30.70 K is the final temperature

Substituting the numbers into the equation, we find

P_2 = P_1 \frac{T_2}{T_1}=(1.049 kPa)\frac{30.70 K}{7.39 K}=4.358 kPa

7 0
4 years ago
Which are base units used in the metric system? Check all that apply.
Shtirlitz [24]

Liters

Grams

Degrees Celsius

The other answer choices are from the imperial system

7 0
4 years ago
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