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juin [17]
3 years ago
10

A loudspeaker diaphragm is vibrating in simple harmonic motion with a frequency of 760 Hz and a maximum displacement of 0.85 mm.

Physics
1 answer:
Alchen [17]3 years ago
5 0

Answer:(a) 4775.2Hz (b) 4.06m/s (c) 19382.15m/s²

Explanation: Given that the frequency of oscilation f, is 760Hz and the maximum displacement x, is 0.85mm= 0.00085m

(a) Angular frequency w= 2πf

w= 2π × 760 = 4775.2Hz

(b) Maximum speed v is given as the product of angular frequency and maximum displacement

V=wx

V= 4775.2 × 0.00085

V= 4.06m/s

(c) The maximum acceleration a

= w²x

= (4775.2)² × (0.00085)

a= 19382.15m/s².

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Answer:

Plate separation of each capacitor is 101.132 °A

Explanation:

The formula to calculate the capacitance in empty space as a function of distance (square parallel plates) is:

C=\epsilon_{0}\frac{Area}{distance}

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3 years ago
An elevator carrying a person of mass m is moving upward and slowing down. How does the magnitude f of the force exerted on the
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The force f of the elevator on the man keeps reducing as the elevator keeps going up while the gravitational force mg keeps increasing moving upwards.

<h3>What is an elevator?</h3>

An elevator is an electrical device that lifts people up and down a tall building or structure.

for the elevator to go up, f > mg.

for the elevator to come down mg > f.

Analysis

since the force on the man is f = ma

where a is the acceleration of the elevator, then it means when a increases,  f will increase and when it decreases, f would decrease. slowing down means a, is decreasing going up and this reduces the force as the elevator keeps going up.

on the other hand, gravity acts faster on bodies that are slower in motion so since g, increases going up, mg would also increase.

Learn more about forces in an elevator : brainly.com/question/13526583

#SPJ1

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3 years ago
In an engine, a piston oscillates with simple harmonic motion so that its position varies according to the expression x= 5.0 cos
lakkis [162]

Answer:

a)   x = 4.33 m ,   b)  w = 2 rad / s ,  f = 0.318 Hz ,  c) a = - 17.31 cm / s²,  

d) T =  3.15 s,  e)  A = 5.0 cm

Explanation:

In this exercise on simple harmonic motion we are given the expression for motion

          x = 5 cos (2t + π / 6)

they ask us for t = 0

a) the position of the particle

      x = 5 cos (π / 6)

      x = 4.33 m

remember angles are in radians

 

b) The general form of the equation is

          x = A cos (w t + Ф)

when comparing the two equations

         w = 2 rad / s

angular velocity and frequency are related

          w = 2π f

           f = w / 2π

           f = 2 / 2pi

           f = 0.318 Hz

c) the acceleration is defined by

      a == d²x / dt²

      a = - A w² cos (wt + Ф)

for t = 0 ,  we substitute

      a = - 5,0 2² cos (π / 6)

      a = - 17.31 cm / s²

d) El period is

          T = 1/f

         T= 1/0.318

         T =  3.15 s

e) the amplitude

        A = 5.0 cm

3 0
3 years ago
A rescue airplane is diving at an angle of 37º below the horizontal with a speed of 250 m/s. It releases a survival package when
alisha [4.7K]

Answer:

<em>The correct option is 1.  720 m</em>

Explanation:

<u>Projectile Motion</u>

When an object is launched in free air (no friction) with an initial speed vo at an angle \theta, it describes a curve which has two components: one in the horizontal direction and the other in the vertical direction. The data provided gives us the initial conditions of the survival package's launch.

\displaystyle V_o=250\ m/s

\displaystyle \theta =-37^o

The initial velocity has these components in the x and y coordinates respectively:

\displaystyle V_{ox}=250\ cos(-37^o)=199.7\ m/s

\displaystyle V_{oy}=250\ sin(-37^o)=-150.5\ m/s

And we know the plane has an altitude of 600 m, so the package will reach ground level when:

\displaystyle y=-600\ m

The vertical distance traveled is given by:

\displaystyle y=V_{oy}\ t-\frac{g\ t^2}{2}=-600

We'll set up an equation to find the time when the package lands

\displaystyle -150.5t-4.9\ t^2=-600

\displaystyle -4.9\ t^2-150.5\ t+600=0

Solving for t, we find only one positive solution:

\displaystyle t=3.6\ sec

The horizontal distance is:

\displaystyle x=V_{ox}.t=199.7\times3.6=720\ m

The correct option is 1.  720 m

6 0
3 years ago
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