(a) The tension the musician must stretch it is 147.82 N.
(b) The percent increase in tension is needed to increase the frequency is 26%.
<h3>Tension in the string</h3>
v = √T/μ
where;
- v is speed of the wave
- T is tension
- μ is mass per unit length = 0.0144 kg / 0.6 m = 0.024 kg/m
v = Fλ
in fundamental mode, v = F(2L)
v = 2FL
v = 2 x 65.4 x 0.6 = 78.48 m/s
v = √T/μ
v² = T/μ
T = μv²
T = 0.024 x (78.48)²
T = 147.82 N
<h3>When the frequency is 73.4 Hz;</h3>
v = 2FL = 2 x 73.4 x 0.6 = 88.08 m/s
T = μv²
T = (0.02)(88.08)²
T = 186.19 N
<h3>Increase in the tension</h3>
= (186.19 - 147.82)/(147.82)
= 0.26
= 0.26 x 100%
= 26 %
Thus, the tension the musician must stretch it is 147.82 N.
The percent increase in tension is needed to increase the frequency is 26%.
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Cube A has more thermal energy than cube B.
Explanation:
It is obvious that cube A has gained more thermal energy compared to cube B.
From the description of the experiment, both cubes had the same temperature which is 50°C. Temperature is the degree of hotness or coldness of a body.
Thermal energy is a form of energy expressed as heat in a body.
Cube A has a higher volume because it has gained more thermal energy than Cube B.
Thermal energy increases the rate of vibration of atoms in the crystal lattice of the solid. The more the thermal energy, the more the vibration. This is why Cube A has expanded so much and changed volume.
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Temperature and heat brainly.com/question/914750
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Answer:7,500J
Explanation:
Work done=force× distance