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larisa86 [58]
3 years ago
6

It is late and Carlos is sliding down a rope from his third-floor window to meet his friend Juan. As he slides down the rope fas

ter and faster, he becomes frightened and grabs harder on the rope, increasing the tension in the rope. As soon as the upward tension in the rope becomes equal to his weight:
Physics
1 answer:
gavmur [86]3 years ago
3 0

Answer:

It would help Carlos stop sliding down and he would stay in his place in the air.

Explanation:

According to Newton's 1st Law of Motion, a body is said to be at rest or uniform motion when no net force is acting on it. This explains that when the tension in the rope becomes equal to Carlos' weight, the net force becomes zero which means the body (Carlos), is at rest and remains in the air instead of sliding down the rope.

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Answer:

11 depth

Explanation:

hh Ismay Patricia

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Bobby tries to push his new big screen TV into the living room. However, Bobby does not push hard enough and cannot move the TV.
Irina18 [472]
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.

<span>Have Bobby as a horizontal force pushing towards/against the tv.
</span><span>Have the force of gravity going downwards from the tv on the floor.
</span><span>Have the force of fric±on between the Foor and the tv

</span>Maybe another force could be bobby's feet pushing from the Foor and his weight (from gravity) bearingdown on his feet. If he didn't weigh more then the tv then he wouldn't be able to put enough pressure<span>on the Foor to create the gripping fric±on force necessary to push the tv</span>
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What sport does not require a high level of fitness
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Rock climbing. Free diving. Sky diving. Dog sledding.
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2 years ago
Newton's First and Second Laws of Motion:Question 3Kepler-10b, the first confirmed terrestrial extrasolar planet, is about 564 l
OleMash [197]

Answer:

F = 85696.5 N = 85.69 KN

Explanation:

In this scenario, we apply Newton's Second Law:

Unbalanced\ Force = ma\\Upthrust - Weight\ of\ Space\ Craft = ma\\F - W = ma\\F - mg = ma\\F = m(g + a)\\

where,

F = Upthrust = ?

m = mass of space craft = 5000 kg

g = acceleration due to gravity on surface of Kepler-10b = (1.53)(9.81 m/s²)

g = 15.0093 m/s²

a = acceleration required = 2.13 m/s²

Therefore,

F = (5000\ kg)(15.0093\ m/s^{2} + 2.13\ m/s^{2})\\

<u>F = 85696.5 N = 85.69 KN</u>

8 0
3 years ago
It is night. Someone who is 4 feet tall is walking away from a street light at a rate of 8 feet per second. The street light is
KiRa [710]

Answer: 4 ft/s

Explanation:

Given

height of man=4 ft

speed of person v=8 ft/s

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Let x be the distance between person and street light and y be the length of his shadow

From diagram

as the two triangle ADE and ABC are similar therefore we can say that

\frac{4}{12}=\frac{y}{x+y}

\frac{1}{3}=\frac{y}{x+y}

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differentiate above Equation w.r.t time we get

\frac{\mathrm{d} x}{\mathrm{d} t}=2\frac{\mathrm{d} y}{\mathrm{d} t}

\frac{\mathrm{d} y}{\mathrm{d} t}=\frac{8}{2}=4 ft/s

6 0
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