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larisa86 [58]
3 years ago
6

It is late and Carlos is sliding down a rope from his third-floor window to meet his friend Juan. As he slides down the rope fas

ter and faster, he becomes frightened and grabs harder on the rope, increasing the tension in the rope. As soon as the upward tension in the rope becomes equal to his weight:
Physics
1 answer:
gavmur [86]3 years ago
3 0

Answer:

It would help Carlos stop sliding down and he would stay in his place in the air.

Explanation:

According to Newton's 1st Law of Motion, a body is said to be at rest or uniform motion when no net force is acting on it. This explains that when the tension in the rope becomes equal to Carlos' weight, the net force becomes zero which means the body (Carlos), is at rest and remains in the air instead of sliding down the rope.

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Una persona tiene 45 años de edad y una masa de 78 kg. ¿Cuántas horas ha vivido? ¿Cuál
Pavel [41]

Answer:

I will answer this in English.

He has 45 years.

a year has 365 days.

a day has 24 hours.

So he has:

45*365*24  hours = 394,200 hours.

His mass is 78 kg,

And we know that 1 slug = 1lbf*ft/s^2

Then, the first step is transform the 78 kg into lbf.

1kg = 2.2 lbf.

then 78kg = 78*2.2 lbf = 171.6lbf.

Now, the weight is m*g, where m is the mass and g is the gravitational acceleration, in this case the gravitational acceleration in ft/s^2 is:

g =  32.2 ft/s^2

Then the weight in slugs is:

W = 32.2ft/s^2*171.6lbf = 5,525.5 slugs

8 0
3 years ago
Two vectors, A and B, have magnitudes of 10 and 15. The cross product of these vectors has magnitude 32. What is the angle betwe
zalisa [80]

Answer:

The Angle between the vector A and B is 12.32°

Explanation:

Given data

|A×B|=32

|A|=10

|B|=15

To find

Angle α

Solution

From Cross product properties we know that

|A*B|=|A||B|Sin\alpha \\32=(10)(15)Sin\alpha\\Sin\alpha=32/150\\\alpha =Sin^{-1}(32/150)\\\alpha  =12.32^{o}

The Angle between the vector A and B is 12.32°

7 0
3 years ago
Read 2 more answers
A solenoid with 385 turns per meter and a diameter of 17.0 cm has a magnetic flux through its core of magnitude 1.28 × 10-4 (T·m
shepuryov [24]

Answer:

(a)The current passes through the solenoid is 11.7 A.

(b) The new current will be one-fourth of the initial current.

Explanation:

Given that,

The number of turns per meter = 385

Diameter of solenoid = 17.0 cm = 17\times 10^{-2} m

Magnetic flux  through core of solenoid \phi = 1.28\times 10^{-4} Tm²

(a)

Magnetic field B= \mu_0nI

\mu_0= 4\pi \times 10^{-7} T/amp m

Cross section area of the solenoid A= \pi \frac{d^2}{4}

                                                             =\pi\frac{ (17\times 10^{-2})^2}{4}  m²

The angle between magnetic field and cross section of the solenoid is \theta =0^\circ

The magnetic flux through a area A with magnetic fie;d B is

\phi = BA cos\theta

\Rightarrow \phi =( \mu_0nI)(\pi \frac{d^2}4)cos \theta

\Rightarrow I =\frac{\phi}{(\mu_0\pi n \frac{d^2}4cos\theta)}

       =\frac{4\phi}{(\mu_0n)(\pi d^2)cos\theta}

      =\frac{1.28\times 10^{-4}\times 4}{(4\pi \times10^{-7}\times385 )\times(\pi\times17\times 10^{-2})^2cos 0^\circ}

     =11.7 A

The current of the solenoid is 11.7 A.

(b)

I =\frac{4\phi}{(\mu_0\pi n d^2cos\theta)}

From the above equation it is clear that, the current is inversely proportional to the square of the diameter of a solenoid.

I\propto \frac1{d^2}.

Consider d' be the new diameter of the solenoid .

Since the new diameter of the solenoid is double of the initial diameter.

That is d'= 2d.

\frac{I}{I'}= \frac{(d')^2}{d^2}

\Rightarrow \frac{I}{I'}=\frac{(2d)^2}{d^2}

\Rightarrow \frac{I}{I'}=4

⇒I=4I'

\Rightarrow I'=\frac{I}{4}

The new current will be one-fourth of the initial current.

7 0
3 years ago
I need help with these questions please
AURORKA [14]

24.A

25.B

26.True

27. False

28.True

7 0
4 years ago
Read 2 more answers
)consider two positively charged particles, one of charge q0 (particle 0) fixed at the origin, and another of charge q1 (particl
I am Lyosha [343]

here force between two particles is given by Coulomb's law where two particles will either repel or attract each other

this force of attraction or repulsion is given by the equation

F = \frac{kq_1 q_2}{r^2}

here we know that

q_1 , q_2 = two point charges

r = distance between two charges

so now we will substitute all values in it

F = \frac{kq_0q_1}{d_1^2}

so above is the force between two point charges

5 0
3 years ago
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