Question

Carlos is driving home after getting some Whataburger for lunch. The Whataburger bag is full of food, and is sitting in the front seat. He is driving east with a speed of 35 m/s. There is another car driving towards him, with a velocity of -25 m/s. Relative to Carlos, how fast is the Whataburger bag moving?

Answer 1

Answer:

Relative to Carlos the Whataburger is moving at 0 speed.

Explanation:

Carlos speed, $V_A$ = 35 m/s

speed of another car, $V_B$ = -25 m/s

The speed of the Whataburger, $V_w$  = 35 m/s since it is in the same car as Carlos.

The relative of the Whataburger to Carlos is given as;

$V = V_A - W_w\\\\V = 35 \ m/s - 35 \ m/s\\V = 0$

Therefore, Relative to Carlos the Whataburger is moving at 0 speed.